Chapter 6, Problem 25A

Calculate the acceleration of a 40-kg crate of softball gear when pulled sideways with net force of 200 N.

To determine

Acceleration of crate of softball gear.

Answer to Problem 25A

  $a=5{\text{m/s}}^2$

Explanation of Solution

Given:

Net force, $F=200\text{N}$

Mass of crate, $m=40\text{kg}$

Formula Used:

From Newton’s second law, the net force is given as

  $F=ma$

Where, $m$ is mass of object and $a$ is acceleration.

Calculation:

On substituting the given values,

  $\begin{array}{l}200=40\times a\\ \Rightarrow a=\frac{200}{40}=5\\ \Rightarrow a=5{\text{m/s}}^2\end{array}$

Conclusion:

Therefore, the acceleration of crate of softball gear is $a=5{\text{m/s}}^2$ .