Chapter 6, Problem 1SAQ

A chemical system produces 155 kJ of heat and does 22 kJ of work. What is ΔE for the surroundings?

a) 177 kJ

b) –177 kJ

c) 133 kJ

d) –133 kJ

Interpretation Introduction

To determine: $\Delta E$ for the surroundings.

Answer to Problem 1SAQ

Solution: (a) $177\text{kJ}$

Explanation of Solution

Given info:

The amount of the heat produced = 155kJ.

The amount of the work done = 22kJ.

$\Delta E=q+w$

where q is the heat produced and w is the work done.

Thus, $\Delta E=155+22=177\text{ kJ}$

Hence, $\Delta E$ for the surroundings is $177\text{kJ}$.