Chapter 6, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

The chemical formula of the compound formed from elements $\text{Ba}$ and $\text{S}$ has to be written.

Answer to Problem 1PE

The chemical formula of the compound formed from elements $\text{Ba}$ and $\text{S}$ is $\text{BaS}\text{.}$

Explanation of Solution

Barium forms ${\text{Ba}}^{\text{2+}}$ and sulfur forms sulfide ${\text{S}}^{\text{2-}\text{.}}.$  The formula of the ions are ${\text{Ba}}^{\text{2+}}$ and ${\text{S}}^{\text{2-}}.$  The smallest number of ${\text{Ba}}^{\text{2+}}$ and ${\text{S}}^{\text{2-}\text{.}}$ are combined to give the sum of charges equal to zero.

  $\begin{array}{l}\left({\text{Ba}}^{\text{2+}}\right)\text{+}\left({\text{S}}^{\text{2-}}\right)\text{=0}\\ \left(\text{2+}\right)\text{+}\left(\text{2-}\right)\text{=0}\end{array}$

The formula is $\text{BaS}\text{.}$

The chemical formula of the compound formed from elements $\text{Ba}$ and $\text{S}$ is $\text{BaS}\text{.}$

(b)

Interpretation Introduction

Interpretation:

The chemical formula of the compound formed from elements $\text{Cs}$ and $\text{P}$ has to be written.

Answer to Problem 1PE

The chemical formula of the compound formed from elements $\text{Cs}$ and $\text{P}$ is ${\text{Cs}}_{\text{3}}\text{P}\text{.}$

Explanation of Solution

Cesium forms ${\text{Cs}}^{\text{+}}$ and phosphorus forms ${\text{P}}^{\text{3-}}\text{.}$  The formula of the ions are ${\text{Cs}}^{\text{+}}$ and ${\text{P}}^{\text{3-}}\text{.}$  The smallest number of ${\text{Cs}}^{\text{+}}$ and ${\text{P}}^{\text{3-}}$ are combined to give the sum of charges equal to zero.  The lowest common multiple of the charges is three.

  $\begin{array}{l}\text{3}\left({\text{Cs}}^{\text{+}}\right)\text{+1}\left({\text{P}}^{\text{3-}}\right)\text{=0}\\ \text{3}\left(\text{1+}\right)\text{+1}\left(\text{3-}\right)\text{=0}\end{array}$

The formula is ${\text{Cs}}_{\text{3}}\text{P}\text{.}$

The chemical formula of the compound formed from elements $\text{Cs}$ and $\text{P}$ is ${\text{Cs}}_{\text{3}}\text{P}\text{.}$

(c)

Interpretation Introduction

Interpretation:

The chemical formula of the compound formed from elements $\text{Li}$ and $\text{Br}$ has to be written.

Answer to Problem 1PE

The chemical formula of the compound formed from elements $\text{Li}$ and $\text{Br}$ is $\text{LiBr}\text{.}$

Explanation of Solution

Lithium forms ${\text{Li}}^{\text{+}}$ and bromine forms ${\text{Br}}^{\text{-}}\text{.}$  The formula of the ions are ${\text{Li}}^{\text{+}}$ and ${\text{Br}}^{\text{-}}\text{.}$  The smallest number of ${\text{Li}}^{\text{+}}$ and ${\text{Br}}^{\text{-}}$ are combined to give the sum of charges equal to zero.

  $\begin{array}{l}\left({\text{Li}}^{\text{+}}\right)\text{+}\left({\text{Br}}^{\text{-}}\right)\text{=0}\\ \left(\text{1+}\right)\text{+}\left(\text{1-}\right)\text{=0}\end{array}$

The formula is $\text{LiBr}\text{.}$

The chemical formula of the compound formed from elements $\text{Li}$ and $\text{Br}$ is $\text{LiBr}\text{.}$

(d)

Interpretation Introduction

Interpretation:

The chemical formula of the compound formed from elements $\text{Mg}$ and $\text{N}$ has to be written.

Answer to Problem 1PE

The chemical formula of the compound formed from elements $\text{Mg}$ and $\text{N}$ is ${\text{Mg}}_{\text{3}}{\text{N}}_{\text{2}}\text{.}$

Explanation of Solution

Magnesium forms ${\text{Mg}}^{\text{2+}}$ and nitrogen forms ${\text{N}}^{\text{3-}}\text{.}$  The formula of the ions are ${\text{Mg}}^{\text{2+}}$ and ${\text{N}}^{\text{3-}}.$  The smallest number of ${\text{Mg}}^{\text{2+}}$ and ${\text{N}}^{\text{3-}}$ are combined to give the sum of charges equal to zero.  The lowest common multiple is $\text{6}\text{.}$

  $\begin{array}{l}\text{3}\left({\text{Mg}}^{\text{2+}}\right)\text{+2}\left({\text{N}}^{\text{3-}}\right)\text{=0}\\ \text{3}\left(\text{2+}\right)\text{+2}\left(\text{3-}\right)\text{=0}\end{array}$

The formula is ${\text{Mg}}_{\text{3}}{\text{N}}_{\text{2}}\text{.}$

The chemical formula of the compound formed from elements $\text{Mg}$ and $\text{N}$ is ${\text{Mg}}_{\text{3}}{\text{N}}_{\text{2}}\text{.}$

(e)

Interpretation Introduction

Interpretation:

The chemical formula of the compound formed from elements $\text{Ca}$ and $\text{I}$ has to be written.

Answer to Problem 1PE

The chemical formula of the compound formed from elements $\text{Ca}$ and $\text{I}$ is ${\text{CaI}}_{\text{2}}\text{.}$

Explanation of Solution

Calcium forms ${\text{Ca}}^{\text{2+}}$ and iodine forms ${\text{I}}^{\text{-}}.$  The formula of the ions are ${\text{Ca}}^{\text{2+}}$ and ${\text{I}}^{\text{-}}\text{.}$  The smallest number of ${\text{Ca}}^{\text{2+}}$ and ${\text{I}}^{\text{-}}$ are combined to give the sum of charges equal to zero.  The lowest common multiple is $\text{2}\text{.}$

  $\begin{array}{l}1\left({\text{Ca}}^{\text{2+}}\right)\text{+2}\left({\text{I}}^{\text{-}}\right)\text{=0}\\ 1\left(\text{2+}\right)\text{+2}\left(\text{1-}\right)\text{=0}\end{array}$

The formula is ${\text{CaI}}_{\text{2}}\text{.}$

The chemical formula of the compound formed from elements $\text{Ca}$ and $\text{I}$ is ${\text{CaI}}_{\text{2}}\text{.}$

(f)

Interpretation Introduction

Interpretation:

The chemical formula of the compound formed from elements $\text{H}$ and $\text{Cl}$ has to be written.

Answer to Problem 1PE

The chemical formula of the compound formed from elements $\text{H}$ and $\text{Cl}$ is $\text{HCl}\text{.}$

Explanation of Solution

Hydrogen forms ${\text{H}}^{\text{+}}$ and chlorine forms ${\text{Cl}}^{\text{-}}\text{.}$  The formula of the ions are ${\text{H}}^{\text{+}}$ and ${\text{Cl}}^{\text{-}}\text{.}$  The smallest number of ${\text{H}}^{\text{+}}$ and ${\text{Cl}}^{\text{-}}$ are combined to give the sum of charges equal to zero.

  $\begin{array}{l}\left({\text{H}}^{\text{+}}\right)\text{+}\left({\text{Cl}}^{\text{-}}\right)\text{=0}\\ \left(\text{1+}\right)\text{+}\left(\text{1-}\right)\text{=0}\end{array}$

The formula is $\text{HCl}\text{.}$

The chemical formula of the compound formed from elements $\text{H}$ and $\text{Cl}$ is $\text{HCl}\text{.}$