(a)
Interpretation:
The chemical formula of potassium cation has to be written.
(b)
Interpretation:
The chemical formula of ammonium has to be written.
(c)
Interpretation:
The chemical formula of copper (I) cation has to be written.
(d)
Interpretation:
The chemical formula of titanium (IV) cation has to be written.
(e)
Interpretation:
The chemical formula of nickel (III) cation has to be written.
(f)
Interpretation:
The chemical formula of cesium cation has to be written.
(g)
Interpretation:
The chemical formula of mercury (II) cation has to be written.
(h)
Interpretation:
The chemical formula of calcium cation has to be written.
(i)
Interpretation:
The chemical formula of lead (II) cation has to be written.
(j)
Interpretation:
The chemical formula of zinc cation has to be written.
(k)
Interpretation:
The chemical formula of silver cation has to be written.
(l)
Interpretation:
The chemical formula of hydrogen cation has to be written.
(m)
Interpretation:
The chemical formula of tin (II) cation has to be written.
(n)
Interpretation:
The chemical formula of iron (III) cation has to be written.

Want to see the full answer?
Check out a sample textbook solution
Chapter 6 Solutions
FOUNDATIONS OF COLLEGE CHEM +KNEWTONALTA
- > You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardDon't use ai to answer I will report you answerarrow_forwardConsider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence pointarrow_forward
- What is the name of the following compound? SiMe3arrow_forwardK Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Searcharrow_forward7 Draw the starting alkyl bromide that would produce this alkyne under these conditions. F Drawing 1. NaNH2, A 2. H3O+ £ 4 Temps to rise Tomorrow Q Search H2arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning

