EBK CONCEPTS OF DATABASE MANAGEMENT
EBK CONCEPTS OF DATABASE MANAGEMENT
9th Edition
ISBN: 9781337670494
Author: Last
Publisher: Cengage Learning
Question
Book Icon
Chapter 6, Problem 10RQ

(a)

To determine

To find the relationship between students, courses and faculty members in the specified relation.

(a)

Expert Solution
Check Mark

Explanation of Solution

The given relation is Student(StudentNum_,CourseNum_,FacultyNum_) .

The above relation Student and Faculty has many-to-many relationship since a new table is generated whose primary key is the combination of all primary key.

Since a faculty teaches many students and a student is taught by many faculties. Therefore, the relation between student and faculty is many-to-many relationship.

The relation between Student and Course has many to many relationships since a student can take many courses and a course can be taken by many students.

After creating new table, the collection of tables is as follows:

Faculty(FacultyNum_,Name,Department)Course(CourseNum_,CourseName)StudentFaculty(StudentNum_,StudentName)Student(StudentNum_,CourseNum_,FacultyNum_)

(b)

To determine

To find the relationship between students, courses and faculty members in the specified relation.

(b)

Expert Solution
Check Mark

Explanation of Solution

The given relation is as follows:

Student(StudentNum_,CourseNum_)Faculty(CourseNum_,FacultyNum_)

Since one student can take many courses and one course is taken by many students.

Therefore, the attributes StudentNum and CourseNum in the Student relation used as the primary key shows the many-to-many relationship between StudentFaculty and Course tables.

The relation Faculty and Course has many-to-many relationship since one faculty can be assigned many course numbers and one course number can be assigned to many faculties.

After creating new table, the collection of tables is as follows:

Faculty(FacultyNum_,CourseNum_)Course(CourseNum_,CourseName)StudentFaculty(StudentNum_,StudentName)Student(StudentNum_,CourseNum_)

(c)

To determine

To find the relationship between students, courses and faculty members in the specified relation.

(c)

Expert Solution
Check Mark

Explanation of Solution

The given relation is as follows:

Student(StudentNum_,CourseNum_)Faculty(CourseNum_,FacultyNum_)StudenFaculty(StudentNum_,CourseNum,_FacultyNum_) .

The relation StudentFaculty and Faculty has many-to-many relationship since many students have assigned many courses.

The relation Faculty and Course has many-to-many relationship as many faculties can be assigned many courses.

The relation StudentFaculty and Course has many-to-many relationship since one faculty can be assigned many course numbers and one course number can be assigned to many faculties.

Also, the relation StudentFaculty and Faculty has many to many relationships since one student is taught by many faculties and one faculty can be assigned to many students.

(d)

To determine

To find the relationship between students, courses and faculty members in the specified relation.

(d)

Expert Solution
Check Mark

Explanation of Solution

The given relation is Student(StudentNum_,CourseNum_,FacultyNum_) .

The above relation Student and Faculty has many-to-many relationship since a new table is generated whose primary key is the combination of all primary key.

Since a faculty teaches many students and a student is taught by many faculties. Therefore, the relation between student and faculty is many-to-many relationship.

The relation between Student and Course has many tomany relationships since a student can take many courses and a course can be taken by many students.

After creating new table the collection of tables are as follows:

Faculty(FacultyNum_,Name,Department)Course(CourseNum_,CourseName)StudentFaculty(StudentNum_,StudentName)Student(StudentNum_,CourseNum_,FacultyNum_)

(e)

To determine

To find the relationship between students, courses and faculty members in the specified relation.

(e)

Expert Solution
Check Mark

Explanation of Solution

The given relation is as follows:

Student(StudentNum_,CourseNum_)Faculty(CourseNum_,FacultyNum_)StudenFaculty(StudentNum_,FacultyNum_) .

The relation Student and Course has many-to-many relationship since many students have assigned many courses.

The relation Faculty and Course has many-to-many relationship since many faculties can be assigned to many subjects.

The relation Student and Faculty has many-to-many relationship since one faculty can be assigned many students and one student can be assigned to many faculties.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
6. What is Race condition? How to prevent it? [2 marks] 7. How many synchronization methods do you know and compare the differences. [2 marks] 8. Explain what are the “mutual exclusion”, “deadlock”, “livelock”, and “eventual entry”, with the traffic intersection as an example like dinning philosophy. [2 marks] 9. For memory allocation, what are the difference between internal fragmentation and external fragmentation. Explain with an example. [2 marks] 10. How can the virtual memory map to the physical memory. Explain with an example. [2 marks]
Your answers normally have 50 words. Less than 50 words will not get marks. 1. What is context switch between multiple processes? [2 marks] 2. Draw the memory layout for a C program. [2 marks] 3. How many states does a process has? [2 marks] 4. Compare the non-preemptitve scheduling and preemptive scheduling. [2 marks] 5. Given 4 process and their arrival times and next CPU burst times, what are the average times and average Turnaround time, for different scheduling algorithms including: a. First Come, First-Served (FCFS) Scheduling [2 marks] b. Shortest-Job-First (SJF) Scheduling [2 marks] c. Shortest-remaining-time-first [2 marks] d. Priority Scheduling [2 marks] e. Round Robin (RR) [2 marks] Process Arrival Time Burst Time P1 0 8 P2 1 9 P3 3 2 P4 5 4
a database with multiple tables from attributes as shown above that are in 3NF, showing PK, non-key attributes, and FK for each table? Assume the tables are already in 1NF. [Hint: 3 tables will result after deducing 1NF -> 2NF -> 3NF]
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781305627482
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Text book image
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781285196145
Author:Steven, Steven Morris, Carlos Coronel, Carlos, Coronel, Carlos; Morris, Carlos Coronel and Steven Morris, Carlos Coronel; Steven Morris, Steven Morris; Carlos Coronel
Publisher:Cengage Learning
Text book image
Principles of Information Systems (MindTap Course...
Computer Science
ISBN:9781305971776
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning
Text book image
A Guide to SQL
Computer Science
ISBN:9781111527273
Author:Philip J. Pratt
Publisher:Course Technology Ptr
Text book image
Fundamentals of Information Systems
Computer Science
ISBN:9781337097536
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning
Text book image
Principles of Information Systems (MindTap Course...
Computer Science
ISBN:9781285867168
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning