Concept explainers
Interpretation:
With three bonding groups and one nonbonding groups about the central atom, the molecular geometry that is associated has to be chosen from the given options.
Concept Introduction:
Information about the number of bonds and types of bonds can be obtained from Lewis structure but the molecular geometry cannot be obtained. Three dimensional arrangement of atoms in a molecule can be given by molecular geometry. Physical and chemical properties are determined by the molecular geometry of the molecule.
Using VSEPR theory and Lewis structure, the molecular geometry of the molecule that contain less number of atoms can be predicted. VSEPR theory uses the information from Lewis structure of the molecule to predict the molecular geometry of the molecule. Main concept of VSEPR theory is that electron pairs that are present in the valence shell adopt arrangement in a way that minimize the repulsion between like charges.
If the central atom contains two electron pairs, then it has to be far apart means, it has to be on opposite side of the nucleus. This means the angle has to be
If the central atom contains three electron pairs, then it has to be far apart means, it has to be on corner of a triangle. This means the angle has to be
If the central atom contains four electron pairs, then it has to be far apart means, it has to be in a tetrahedral arrangement. This means the angle has to be
The collection of valence electron that is present in localized region about central atom in a molecule is known as VSEPR electron group. This may contain two electrons, four electrons, or six electrons. The electron group that contain four and six electrons repel each other.
Tetrahedral VSEPR electron group:
The four electron pairs can be of three VSEPR electron groups. They are 4 bonding electron groups, 3 bonding and 1 nonbonding electron groups, and 2 bonding and 2 nonbonding electron groups. The molecular geometry that is associated with 4 bonding electron groups is tetrahedral. The molecular geometry that is associated with 3 bonding and 1 nonbonding electron groups is trigonal pyramidal. The molecular geometry that is associated with 2 bonding and 2 nonbonding electron groups is angular.
Trigonal planar VSEPR electron group:
The three electron pairs can be of two VSEPR electron groups. They are 3 bonding electron groups, and 2 bonding and 1 nonbonding electron groups. The molecular geometry that is associated with 3 bonding electron groups is trigonal planar. The molecular geometry that is associated with 2 bonding and 1 nonbonding electron groups is angular.
Linear VSEPR electron group:
The two electron pairs can be of only one VSEPR electron groups. It is only 2 bonding electron groups and the geometry associated with it is linear geometry.
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Chapter 5 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forward
- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Rank the compounds in each group below according to their reactivity toward electrophilic aromatic substitution (most reactive = 1; least reactive = 3). Place the number corresponding to the compounds' relative reactivity in the blank below the compound. a. CH₂F CH3 F b. At what position, and on what ring, is bromination of phenyl benzoate expected to occur? Explain your answer. :0: C-O phenyl benzoate 6.Consider the reaction below to answer the following questions. A B C NO₂ FeBr3 + Br₂ D a. The nucleophile in the reaction is: BODADES b. The Lewis acid catalyst in the reaction is: C. This reaction proceeds d. Draw the structure of product D. (faster or slower) than benzene.arrow_forwardPart 2. A solution of 6.00g of substance B in 100.0mL of aqueous solution is in equilibrium, at room temperature, wl a solution of B in diethyl ether (ethoxyethane) containing 25.0 g of B in 50.0 mL 9) what is the distribution coefficient of substance B b) what is the mass of B extracted by shaking 200 ml of an aqueous solution containing 10g of B with call at room temp): i) 100 mL of diethyl ether ii) 50ml of diethyl ether twice iii) 25ml of diethyl ether four timesarrow_forward- Rank the following groups of compounds from most acidic (1) to least acidic (4). Place the number corresponding to the compound's relative rank in the blank below the structure. a. NO₂ NO₂ CH2CH2CH2CH2OH CH3 CH3CH2CHOH CH3CH2CH2CH2OH NO₂ CH3CHCH2CH2OH b. OH OH CH₂OH CO₂H HC CN CN CNarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
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