Explanation Given The stated equation is, CuO ( s ) + H 2 ( g ) → Cu ( s ) + H 2 O ( l ) The enthalpy change of the reaction is calculated by the formula,] Δ H r e a c t i o n ° = ∑ n Δ H f ° ( products ) − ∑ m Δ H f ° ( reactancts ) = [ Δ H f ° ( Cu ) + Δ H f ° ( H 2 O ) ] − [ Δ H f ° ( CuO ) + Δ H f ° ( H 2 ) ] Where, Δ H r e a c t i o n ° is the enthalpy change of the reaction. Δ H f ° ( Cu ) is the enthalpy change of formation of copper. Δ H f ° ( H 2 O ) is the enthalpy change of formation of water. Δ H f ° ( CuO ) is the enthalpy change of formation of copper oxide. Δ H f ° ( H 2 ) is the enthalpy change of formation of hydrogen

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Chapter 5.7, Problem 5.12.2PE

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To determine: The standard enthalpy of formation of CuO(s) .

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Chapter 5.7, Problem 5.12.1PE

Chapter 5.8, Problem 5.13.1PE

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The standard enthalpy of formation of CuO ( s ) .

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