a.
The speed of each ship and express the answer in knots.
Speed of ship A is
Given information:
Two ships leave the common port at 8:00 a.m. and travel at a constant rate of speed. The portions of the log for the both ships are shown in the table below.
Calculation:
The distance of the ship from the port at 9:00 a.m. was
Similarly, ship B traveled a distance of
b.
The angle of the intersection of course of the two ships.
The angle of the intersection of course of the two ships is
Given information:
Two ships leave the common port at 8:00 a.m. and travel at a constant rate of speed. The portions of the log for the both ships are shown in the table below.
Calculation:
The distance of the ship from the port at 9:00 a.m. was
Similarly, ship B traveled a distance of
Now, let
Now, use the cosine formula to find the angle
Therefore, the angle of the intersection of course of the two ships is
c.
The distance between the ships at 12:00 noon.
The ships are
Given information:
Two ships leave the common port at 8:00 a.m. and travel at a constant rate of speed. The portions of the log for the both ships are shown in the table below.
Calculation:
The distance traveled by ship A by 12:00 noon is
From part (b), the angle of intersection of the courses of the two ships is
So, the triangle representing the distance of each ship from the port and the distance between them can be shown as shown below.
Now, use the cosine formula to find the distance
Therefore, the ships are
Chapter 5 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
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