PRECALCULUS:GRAPHICAL,...-NASTA ED.
PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780134672090
Author: Demana
Publisher: PEARSON
Expert Solution & Answer
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Chapter 5.5, Problem 15E
Solution

To state: Whether the given measurements determine zero, one or two triangles.

Two triangles are possible with the measurements C=36°, c=16, a=17.

Given data:

  C=36°, c=16, a=17

Formula used:

Law of Sines: In any ΔABC with angles A,B and C having opposite sides a,b and c

respectively then the following equation is true:

  sinAa=sinBb=sinCc

Calculation:

Calculate angle A using Law of Sines.

  sin36°16=sinA17sinA=17×sin36°16sinA=17×0.5816A=sin−10.616A=38.647°

Calculate angle B .

  ∠A+∠B+∠C=180°∠B=180°−36°+38.647°∠B=105.353°

When angle A is acute, a triangle is possible with angles 38.647°, 105.353° and 36° .

Let us suppose angle A is obtuse.

  ∠A=180°−38.647°=141.353°

Calculate angle B for this angle of A .

  ∠A+∠B+∠C=180°∠B=180°−36°+141.353°∠B=2.647°

Thus, when angle A is obtuse, another triangle is also possible with angles 141.353°, 2.647° and 36° .

Therefore, two triangles are possible with the measurements C=36°, c=16, a=17.

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Chapter 5.5, Problem 14E
Next
Chapter 5.5, Problem 16E

Chapter 5 Solutions

PRECALCULUS:GRAPHICAL,...-NASTA ED.

Ch. 5.1 - Prob. 1QRCh. 5.1 - Prob. 2QRCh. 5.1 - Prob. 3QRCh. 5.1 - Prob. 4QRCh. 5.1 - Prob. 5QRCh. 5.1 - Prob. 6QRCh. 5.1 - Prob. 7QRCh. 5.1 - Prob. 8QRCh. 5.1 - Prob. 9QRCh. 5.1 - Prob. 10QR
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Prob. 74ECh. 5.3 - Prob. 75ECh. 5.4 - Prob. 1QRCh. 5.4 - Prob. 2QRCh. 5.4 - Prob. 3QRCh. 5.4 - Prob. 4QRCh. 5.4 - Prob. 5QRCh. 5.4 - Prob. 6QRCh. 5.4 - Prob. 7QRCh. 5.4 - Prob. 8QRCh. 5.4 - Prob. 9QRCh. 5.4 - Prob. 10QRCh. 5.4 - Prob. 1ECh. 5.4 - Prob. 2ECh. 5.4 - Prob. 3ECh. 5.4 - Prob. 4ECh. 5.4 - Prob. 5ECh. 5.4 - Prob. 6ECh. 5.4 - Prob. 7ECh. 5.4 - Prob. 8ECh. 5.4 - Prob. 9ECh. 5.4 - Prob. 10ECh. 5.4 - Prob. 11ECh. 5.4 - Prob. 12ECh. 5.4 - Prob. 13ECh. 5.4 - Prob. 14ECh. 5.4 - Prob. 15ECh. 5.4 - Prob. 16ECh. 5.4 - Prob. 17ECh. 5.4 - Prob. 18ECh. 5.4 - Prob. 19ECh. 5.4 - Prob. 20ECh. 5.4 - Prob. 21ECh. 5.4 - Prob. 22ECh. 5.4 - Prob. 23ECh. 5.4 - Prob. 24ECh. 5.4 - Prob. 25ECh. 5.4 - Prob. 26ECh. 5.4 - Prob. 27ECh. 5.4 - Prob. 28ECh. 5.4 - Prob. 29ECh. 5.4 - Prob. 30ECh. 5.4 - Prob. 31ECh. 5.4 - Prob. 32ECh. 5.4 - Prob. 33ECh. 5.4 - Prob. 34ECh. 5.4 - Prob. 35ECh. 5.4 - Prob. 36ECh. 5.4 - Prob. 37ECh. 5.4 - Prob. 38ECh. 5.4 - Prob. 39ECh. 5.4 - Prob. 40ECh. 5.4 - Prob. 41ECh. 5.4 - Prob. 42ECh. 5.4 - 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Prob. 24ECh. 5.5 - Prob. 25ECh. 5.5 - Prob. 26ECh. 5.5 - Prob. 27ECh. 5.5 - Prob. 28ECh. 5.5 - Prob. 29ECh. 5.5 - Prob. 30ECh. 5.5 - Prob. 31ECh. 5.5 - Prob. 32ECh. 5.5 - Prob. 33ECh. 5.5 - Prob. 34ECh. 5.5 - Prob. 35ECh. 5.5 - Prob. 36ECh. 5.5 - Prob. 37ECh. 5.5 - Prob. 38ECh. 5.5 - Prob. 39ECh. 5.5 - Prob. 40ECh. 5.5 - Prob. 41ECh. 5.5 - Prob. 42ECh. 5.5 - Prob. 43ECh. 5.5 - Prob. 44ECh. 5.5 - Prob. 45ECh. 5.5 - Prob. 46ECh. 5.5 - Prob. 47ECh. 5.5 - Prob. 48ECh. 5.5 - Prob. 49ECh. 5.5 - Prob. 50ECh. 5.5 - Prob. 51ECh. 5.5 - Prob. 52ECh. 5.5 - Prob. 53ECh. 5.5 - Prob. 54ECh. 5.5 - Prob. 55ECh. 5.5 - Prob. 56ECh. 5.5 - Prob. 57ECh. 5.6 - Prob. 1QRCh. 5.6 - Prob. 2QRCh. 5.6 - Prob. 3QRCh. 5.6 - Prob. 4QRCh. 5.6 - Prob. 5QRCh. 5.6 - Prob. 6QRCh. 5.6 - Prob. 7QRCh. 5.6 - Prob. 8QRCh. 5.6 - Prob. 9QRCh. 5.6 - Prob. 10QRCh. 5.6 - Prob. 1ECh. 5.6 - Prob. 2ECh. 5.6 - Prob. 3ECh. 5.6 - Prob. 4ECh. 5.6 - Prob. 5ECh. 5.6 - Prob. 6ECh. 5.6 - Prob. 7ECh. 5.6 - Prob. 8ECh. 5.6 - Prob. 9ECh. 5.6 - Prob. 10ECh. 5.6 - 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