BIOLOGY >PRINT UPGRADE<
11th Edition
ISBN: 9780357091586
Author: Solomon
Publisher: CENGAGE L
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Chapter 55.3, Problem 3C
Summary Introduction
To determine: Some factors that produce regional differences in precipitation.
Introduction: The average weather condition with extremes that occur in a specific location is known as climate. The two most important factors that define the climate of a specific area are precipitation and temperature.
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Chapter 55 Solutions
BIOLOGY >PRINT UPGRADE<
Ch. 55.1 - Summarize the concept of energy flow through a...Ch. 55.1 - Explain typical pyramids of numbers, biomass, and...Ch. 55.1 - Distinguish between gross primary productivity and...Ch. 55.1 - VISUALIZE Draw a diagram tracing energy flow...Ch. 55.1 - What are trophic levels, and how are they related...Ch. 55.1 - How do gross primary productivity (GPP) and net...Ch. 55.2 - Describe the main steps in each of these...Ch. 55.2 - What are the roles of the following processes in...Ch. 55.2 - VISUALIZE Draw a diagram showing the five steps in...Ch. 55.2 - How does the phosphorus cycle proceed without a...
Ch. 55.3 - Summarize the effects of solar energy on Earths...Ch. 55.3 - Discuss the roles of solar energy and the Coriolis...Ch. 55.3 - Give two causes of regional precipitation...Ch. 55.3 - Discuss the effects of fire on certain ecosystems.Ch. 55.3 - What basic forces determine the circulation of the...Ch. 55.3 - What basic forces produce the main ocean currents?Ch. 55.3 - Prob. 3CCh. 55.4 - Briefly describe some of the long-term ecological...Ch. 55.4 - Prob. 1CCh. 55 - The movement of matter is _______________ in...Ch. 55 - A complex of interconnected food chains in an...Ch. 55 - The quantitative estimate of the total amount of...Ch. 55 - Which of the following equations shows the...Ch. 55 - Which of the following processes increase(s) the...Ch. 55 - In the nitrogen cycle, gaseous nitrogen is...Ch. 55 - Test Your Understanding 7. The conversion of...Ch. 55 - Which biogeochemical cycle does not have a gaseous...Ch. 55 - Test Your Understanding 9. Which of the following...Ch. 55 - Test Your Understanding 10 The periodic warming of...Ch. 55 - Test Your Understanding 11 A mountain range may...Ch. 55 - VISUALIZE Draw the simplest stable ecosystem you...Ch. 55 - PREDICT How might a food web change if all...Ch. 55 - Why is the cycling of matter essential to the...Ch. 55 - What would happen to the nitrogen cycle if all...Ch. 55 - Test Your Understanding 16 Would the microclimate...Ch. 55 - Test Your Understanding 17 INTERPRET DATA Examine...Ch. 55 - INTERTRET DATA Scientists have compiled databases...Ch. 55 - SCIENCE, TECHNOLOGY, AND SOCIETY How do humans...
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- You implant an FGF10-coated bead into the anterior flank of a chicken embryo, directly below the level of the wing bud. What is the phenotype of the resulting ectopic limb? Briefly describe the expected expression domains of 1) Shh, 2) Tbx4, and 3) Tbx5 in the resulting ectopic limb bud.arrow_forwardDesign a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forward
- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
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