A respiratory cycle is defined as the beginning of one breath to the beginning of the next breath. The rate of air intake r (in L/sec) during a respiratory cycle for a physically fit male can be approximated by r ( t ) = 0.9 sin π 3.5 t where t is the number of seconds into the cycle. A positive value for r represents inhalation and a negative value represents exhalation. a. How long is the respiratory cycle? b. What is the maximum rate of air intake? c. Graph one cycle of the function. On what interval does inhalation occur? On what interval does exhalation occur?
A respiratory cycle is defined as the beginning of one breath to the beginning of the next breath. The rate of air intake r (in L/sec) during a respiratory cycle for a physically fit male can be approximated by r ( t ) = 0.9 sin π 3.5 t where t is the number of seconds into the cycle. A positive value for r represents inhalation and a negative value represents exhalation. a. How long is the respiratory cycle? b. What is the maximum rate of air intake? c. Graph one cycle of the function. On what interval does inhalation occur? On what interval does exhalation occur?
Solution Summary: The author explains how the rate of air intake r (in L/sec) during a respiratory cycle is approximated by the function AmathrmsinBx whose period is
A respiratory cycle is defined as the beginning of one breath to the beginning of the next breath. The rate of air intake r (in L/sec) during a respiratory cycle for a physically fit male can be approximated by
r
(
t
)
=
0.9
sin
π
3.5
t
where t is the number of seconds into the cycle. A positive value for r represents inhalation and a negative value represents exhalation. a. How long is the respiratory cycle? b. What is the maximum rate of air intake? c. Graph one cycle of the function. On what interval does inhalation occur? On what interval does exhalation occur?
Solve the system of equation for y using Cramer's rule. Hint: The
determinant of the coefficient matrix is -23.
-
5x + y − z = −7
2x-y-2z = 6
3x+2z-7
eric
pez
Xte
in
z=
Therefore, we have
(x, y, z)=(3.0000,
83.6.1 Exercise
Gauss-Seidel iteration with
Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i
Tol=10 to solve the following systems:
1.
5x-y+z = 10
2x-8y-z=11
-x+y+4z=3
iteration (x
Assi 2
Assi 3.
4.
x-5y-z=-8
4x-y- z=13
2x - y-6z=-2
4x y + z = 7
4x-8y + z = -21
-2x+ y +5z = 15
4x + y - z=13
2x - y-6z=-2
x-5y- z=-8
realme Shot on realme C30
2025.01.31 22:35
f
Use Pascal's triangle to expand the binomial
(6m+2)^2
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