Concept explainers
Introduction: All the organisms interact with each other and with the environment to survive. The branch of science that deals with the study of the interaction of organism and nature is called ecology. Behavioral ecology is a type of ecology that studies the behavior of a species.

Answer to Problem 1TY
Correct answer: The proximate reason for the male deer fighting over females is the changes in day length. Hence, the correct answer is option d.
Explanation of Solution
Reason for correct answer:
Proximate causes are the genetic and physiological factors that influence the behavioral pattern of organisms. It has been observed that the male deer fight with each other to mate with female deer. This is because of the changes in the day length which brings hormonal changes in male deer. These are physiological changes as the male deer fight only in case of altered day length and not in the day with normal length. Therefore, the proximate cause of male deer fighting over female is changes in day length.
Option d. is given as “Because changes in day length stimulate this behavior”.
The changes in day length stimulate behavior that causes the male deer to fight over females. Hence, the correct answer is option d.
Reasons for incorrect answer:
Option a. is given as, “To determine their supremacy over other males”.
Proximate causes occur due to genetic and physiological factors. The determination of supremacy over other males is a social factor. It does not show any genetic or physiological pattern. Determining supremacy is not a proximate cause of male deer fighting over females. Hence, option a. is incorrect.
Option b. is given as, “To injure other males so that those males cannot mate with the females”.
The proximate causes include two factors, namely genetic and physiological. Any attack on male deer to reduce their mating chances is not a proximate cause as it does not include any genetic or physiological factor. Hence, option b. is incorrect.
Option c. is given as, “To maximize the number of genes the male deer pass on”.
Proximate causes include genetic and behavioral factors. The number of genes is a genetic factor. However, maximizing the gene number cannot be achieved by male deer fighting over females. Hence, option c. is incorrect.
Option e. is given as, “Because fighting helps rid the herd of weaker individuals”.
The fighting of males to get rid of weaker individuals cannot be a proximate cause. This is because, it does not include any genetic or physiological factors. Hence, option e. is incorrect.
Hence, the options a., b., c., and e. are incorrect.
Therefore, the proximate cause of the male deer fighting over the female deer is changes in day length.
Want to see more full solutions like this?
Chapter 55 Solutions
Biology
- 9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…arrow_forwardNormal dive (for diving humans) normal breathing dive normal breathing Oz level CO2 level urgent need to breathe Oz blackout zone high CO2 triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. How might the location and slope of the O₂ line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO₂ line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?arrow_forwardforaging/diet type teeth tongue stomach intestines cecum Insectivory numerous, spiky, incisors procumbentExample: moleExample: shrew -- simple short mostly lacking Myrmecophagy absent or reduced in numbers, peg-likeExample: tamandua anteater extremely long simple, often roughened short small or lacking Terrestrial carnivory sharp incisors; long, conical canines; often carnassial cheek teeth; may have crushing molarsExample: dog -- simple short small Aquatic carnivory homodont, spiky, numerousExample: common dolphin -- simple or multichambered (cetaceans only) variable small or absent Sanguinivory very sharp upper incisors; reduced cheek teethExample: vampire bat grooved tubular, highly extensible long small or lacking Herbivory (except nectivores) incisors robust or absent; canines reduced or absent; diastema; cheek teeth enlarged with complex occlusal surfacesExample: beaver -- simple (hindgut fermenters) or multichambered (ruminants) long large Filter feeding none…arrow_forward
- 3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 པར『ན་ cm 30 Species B 4/3, 1/1, 2/2, 4/4 cm 10 Species C 0/4, 0/0,3/3, 3/3 020arrow_forward3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 cm 30 Species B 0/4, 0/0, 3/3, 3/3 cm 10 Species C 4/3, 1/1, 2/2, 4/4 E 0 cm 20 AILarrow_forwardNormal dive (for diving humans) normal breathing dive normal breathing Oz level CO₂ level urgent need to breathe Oz blackout zone high CO₂ triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. • How might the location and slope of the O2 line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO2 line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?arrow_forward
- How much ATP will be produced during the following metabolic scenario: Aerobic respiration of a 5mM lipid solution that is made up of one glycerol and an 8-carbon fatty acid and 12-carbon fatty acid. Recall that when glycerol breaks down to Glyceraldehyde-3-phosphate it costs one ATP but your get an extra FADH2. Every two carbons of a fatty acid break down to one acetyl-CoA. Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardIf a bacterium using aerobic respiration was to degrade one small protein molecule into 8 molecules of pyruvic acid, how many ATP would that cell make? Assume there is no other carbon source. Units cannot be entered in this style of question but the units of your answer should be in molecules of ATP.arrow_forwardIf a bacterium using aerobic respiration was to degrade a 30 mM solution of citric acid, how many ATP would that cell make? Assume no other carbon source is available. Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forward
- How much ATP will be produced during the following metabolic scenario: Aerobic respiration of a 5mM lipid solution that is made up of one glycerol and an 8-carbon fatty acid and 12-carbon fatty acid. Recall that when glycerol breaks down to Glyceraldehyde-3-phosphate it costs one ATP but your get an extra FADH2. Every two carbons of a fatty acid break down to one acetyl-CoA. (pathways will be provided on the exam) Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardWhen beta-lactamase was isolated from Staphylcoccus aureus and treated with a phosphorylating agent, only the active site, serine was phosphorylated. Additionally, the serine was found to constitute 0.35% (by weight) of this beta-lactamase enzyme. Using this, calculate the molecular weight of this enzyme and estimate the number of amino acids present in the polypeptide.arrow_forwardBased on your results from the Mannitol Salt Agar (MSA) media, which of your bacteria were mannitol fermenters and which were not mannitol fermenters?arrow_forward
- Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning


