Explanation The change in volume flow rate of the pool is expressed as follows. d V pool d t = V ˙ i − V ˙ e (I) Here, the change in volume flow rate of the pool is d V pool d t , the inlet volume flow rate is V ˙ i and the exit volume flow rate is V ˙ e . Rearrange the Equation (I) to obtain the inlet volume flow rate ( V ˙ in ) . V ˙ in = d V pool d t + V ˙ out (II) Write the formula for change in volume flow rate of the pool. d V pool d t = A pool c .s V level = ( 6 m × 9 m ) V level (III) Here, the cross-sectional area of the pool is A pool c .s and the rate of water level rise in the pool is V level . Write the formula for exit volume flow rate ( V ˙ e ) . V ˙ e = A e V e = π D 2 4 V e (IV) Here, the cross-sectional area of the exit orifice is A e , the diameter of the orifice is D and the velocity at exit orifice is V e . Conclusion: Substitute 2.5 cm/min for V level in Equation (III). d V pool d t = ( 6 m × 9 m ) ( 2.5 cm/min ) = 54 m 2 ( 2

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ISBN: 9781259822674

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

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Chapter 5.5, Problem 136RP

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The rate at which the water is supplied to the pool, in m3/s.

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Chapter 5.5, Problem 135P

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The rate at which the water is supplied to the pool, in m 3 /s .

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