Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Question
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Chapter 5.4, Problem 82E

(a)

To determine

Tojustify: Thestatement “ sin(u+v)≠sinu+sinv ” using the given figure.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The given graph is shown in figure (1).

  Precalculus with Limits: A Graphing Approach, Chapter 5.4, Problem 82E , additional homework tip 1

Figure (1)

Calculation:

From the given figure, let’s consider the estimated values.

  sinu=0.7, sinv=0.7, sin(u+v)=0, sin(u−v)=−1

Calculate the sum of sinu and sinv .

  sinu+sinv=0.7+0.7=1.4≠0

So, sin(u+v)≠sinu+sinv .

Therefore, the statement “ sin(u+v)≠sinu+sinv ” is proved.

(b)

To determine

To justify: Thestatement “ sin(u−v)≠sinu−sinv ” using the given figure.

(b)

Expert Solution
Check Mark

Answer to Problem 82E

The statement “ sin(u−v)≠sinu−sinv ” is proved.

Explanation of Solution

Given information:

The given graph is shown in figure (1).

  Precalculus with Limits: A Graphing Approach, Chapter 5.4, Problem 82E , additional homework tip 2

Figure (1)

Calculation:

From the given figure, let’s consider the estimated values.

  sinu=0.7, sinv=0.7, sin(u+v)=0, sin(u−v)=−1

Calculate the difference of sinu and sinv .

  sinu−sinv=0.7−0.7=0≠−1

So, sin(u−v)≠sinu−sinv .

Therefore, the statement “ sin(u−v)≠sinu−sinv ” is proved.

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Chapter 5.4, Problem 81E
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Chapter 5.4, Problem 83E

Chapter 5 Solutions

Precalculus with Limits: A Graphing Approach

Ch. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5ECh. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10E
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Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
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