Understanding Motor Controls
4th Edition
ISBN: 9781337798686
Author: Stephen L. Herman
Publisher: Delmar Cengage Learning
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Question
Chapter 54, Problem 4RQ
To determine
The average output impedance of a 741 operational amplifier.
Expert Solution & Answer
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Students have asked these similar questions
4. A circuit contains a 20-2 resistor and
an inductor with an inductance of
0.093 H. If the circuit has a frequency
of 60 Hz, what is the total impedance
of the circuit?
5. An R-L series circuit has a power
factor of 86%. By how many degrees
are the voltage and current out of
phase with each other?
6. An R-L series circuit has an apparent
power of 230 VA and a true power of
180 W. What is the reactive power?
7. The resistor in an R-L series circuit
has a voltage drop of 53 V, and the
inductor has a voltage drop of 28 V.
What is the applied voltage of the
circuit?
15. Find the value of R, that will produce the indicated closed-loop gain in each amplifier in Figure 12-66
Ry
W
Aj=50
ww
1.0k
Figure 12-66
10 kn
Ag=-300
Aj=8
12 k
V₁₂₁M
2.2k
(d)
Ag=-75
kindly answer number 1,2,3 ONLY
Chapter 54 Solutions
Understanding Motor Controls
Ch. 54 - Prob. 1RQCh. 54 - Prob. 2RQCh. 54 - Prob. 3RQCh. 54 - Prob. 4RQCh. 54 - Prob. 5RQCh. 54 - Prob. 6RQCh. 54 - Name two effects of negative feedback.Ch. 54 - Refer to Figure 548. If resistor R1 is 200 ohms...Ch. 54 - Refer to Figure 54–9. If resistor R1 is 470 ohms...Ch. 54 - What is the purpose of the hysteresis loop when...
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- Refer to Figure 54–9. If resistor R1 is 470 ohms and resistor R2 is 47 kilohms, what is the gain of the amplifier? Figure 54-9 Inverting amplifier connection.arrow_forwardRefer to Figure 548. If resistor R1 is 200 ohms and resistor R2 is 10 kilohms, what is the gain of the amplifier? Figure 548 Noninverting amplifier connection.arrow_forwardIn the experiment No.4, the core loss component current is given by_ Ic Sinôo lo Sindo lc Cos&o lo Cosoarrow_forward
- 9. Identify the resistance of 5 point the Following Five Band Resistor * 60M Ohms +5% O 4000K Ohms +5% O 2000K Ohm +5%arrow_forward?What is the gain of the system (output/input) given below 2 input output 12 3 1/4 no one of these 36 -10 zero 90 13arrow_forwardбли R1 20 1. For the amplifier below, please answer the following questions www R2 40 Vs + R3 حشش A. Calculate Vs'/Vs B. Calculate V1/Vs' C. Calculate V2/V1 D. Calculate VL/V2 Vcc1 = +/- 12 V V1 ww R6 R4 50 25 Ω R5 750 A ww R7 10 Ω + Vcc2 №2 ww R8 502 VL E. What is VL/Vs? F. What is the linear region of Vs due to the first amplifier? G. Decide what Vcc2 given the linear region of Vs (part F) such that the output of V2 does not saturate. R9 5Qarrow_forward
- 1. For the circuit below: 11 10 A ли R2 10 Ω a. Calculate I₂ b. Calculate V2 R1 ли 55 5 Ω ли R3 2.5 Ω 12 R4 + 2.5 Ω Vaarrow_forwardIf the impedance Z1 = 10 +j10 and the impedance Z2 = 10 - j0 are connected in series, the equivalent impedance would be: O A. 20-j10 ohms O B. 20+ j20 ohms O C. None of the other choices are correct O D. 20 ohms O E. 20+ j 10 ohmsarrow_forwardExample 7-3. A 460-V, 25-hp. 60-Hz, four-pole, Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit: - 0.641n X,-1.106 N R2 - 0.332 N X2 = 0.464 XM - 26.3 N The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped in with the rotational losses. For a rotor slip of 2.2 percent at the rated voltage and rated frequency, find the motor's (a) Speed (b) Stator current (c) Povwer factor (d) Peony and Pout (e) Tiad and Toad Efficiencyarrow_forward
- b24 Find the rms value for the following waveform over one full cycle. 40(V) -1 cycle - 16 7 8 9 10 11 12 (S) -1arrow_forwardQ4 Find V1 and V2 in the circuit shown below. Also calculate 11 and 12, and the power dissipated in the 120 And 400 resistors. 15 V 12 Ω ww + 60 ww www. 10 Ω + www iz 40 Ωarrow_forwardThe following data were obtained on a 50 kVA 2400/120 V transformer: Open circuit test, instruments on low voltage side: Waltmeter reading = 396 Watts Ammeter reading = 9.65 amperes Voltmeter reading = 120 Volts Short circuit test, instruments on high voltage side: Waltmeter reading = 810 Watts Ammeter reading = 20.8 amperes Voltmeter reading = 92 Volts Find the efficiency when rated kVA is delivered to a load having a power factor of 0.8 lagging.The following data were obtained on a 50 kVA 2400/120 V transformer : Open circuit test, instruments on low voltage side: Waltmeter reading = 396 Watts Ammeter reading = 9.65 amperes Voltmeter reading = 120 Volts Short circuit test, instruments on high voltage side: Waltmeter reading = 810 Watts Ammeter reading = 20.8 amperes Voltmeter reading = 92 Volts Find the efficiency when rated kVA is delivered to a load having a power factor of 0.8 lagging.arrow_forward
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