Organic Chemistry, Binder Ready Version
2nd Edition
ISBN: 9781118454312
Author: David R. Klein
Publisher: WILEY
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Question
Chapter 5.4, Problem 19PTS
Interpretation Introduction
Interpretation:
To calculate the enantiomeric excess (ee) of given molecules.
Concept Introduction:
Enantiomeric excess: The (ee) is a measurement of purity for chiral substances, and its reflected the degree to which a sample contains one enantiomer in greater amounts then the other.
Consider for simple example the (R)-enantiomers (86%) exceeds the percentage of the (S)-enantiomers (14%) has 86%-14%=72%. Further the substance that is single pure enantiomer (100% ee) is called homo chiral or optically active molecule.
To find: The given molecule enantiomeric excess should be identified.
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Naming and drawing secondary
Write the systematic (IUPAC) name for each of the following organic molecules:
CH3
Z
structure
CH3
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CH2
N-CH3
CH3-CH2-CH2-CH-CH3
NH
CH3-CH-CH2-CH2-CH2-CH2-CH2-CH3
Explanation
Check
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name
☐
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G
C
This question shows how molecular orbital (MO) theory can be used to understand the chemical
properties of elemental oxygen O₂ and its anionic derivative superoxide Oz.
a)
Draw the MO energy diagram for both O2 and O2. Clearly label your diagram with atomic orbital names
and molecular orbital symmetry labels and include electrons.
Draw the Lewis structure of O2. How does the MO description of O2 differ from the Lewis structure, and
how does this difference relate to the high reactivity and magnetic properties of oxygen?
) Use the MO diagram in (a) to explain the difference in bond length and bond energy between superoxide
ion (Oz, 135 pm, 360 kJ/mol) and oxygen (O2, 120.8 pm, 494 kJ/mol).
Please draw
Chapter 5 Solutions
Organic Chemistry, Binder Ready Version
Ch. 5.1 - Prob. 1LTSCh. 5.1 - Prob. 1PTSCh. 5.2 - Prob. 2LTSCh. 5.2 - Prob. 5ATSCh. 5.2 - Prob. 3LTSCh. 5.3 - Prob. 4LTSCh. 5.3 - Prob. 10ATSCh. 5.3 - Prob. 11ATSCh. 5.4 - Prob. 5LTSCh. 5.4 - Prob. 12PTS
Ch. 5.4 - Prob. 13PTSCh. 5.4 - Prob. 14PTSCh. 5.4 - Prob. 15ATSCh. 5.4 - Prob. 16ATSCh. 5.4 - Prob. 6LTSCh. 5.4 - Prob. 17PTSCh. 5.4 - Prob. 18PTSCh. 5.4 - Prob. 19PTSCh. 5.4 - Prob. 20ATSCh. 5.5 - Prob. 7LTSCh. 5.5 - Prob. 21PTSCh. 5.5 - Prob. 22ATSCh. 5.6 - Prob. 23CCCh. 5.6 - Prob. 24CCCh. 5.6 - Prob. 25CCCh. 5.6 - Prob. 8LTSCh. 5.6 - Prob. 26PTSCh. 5.6 - Prob. 27ATSCh. 5.6 - Prob. 28ATSCh. 5.7 - Prob. 9LTSCh. 5.7 - Prob. 29PTSCh. 5.7 - Prob. 30ATSCh. 5.7 - Prob. 31ATSCh. 5 - Prob. 32PPCh. 5 - Prob. 33PPCh. 5 - Prob. 34PPCh. 5 - Prob. 35PPCh. 5 - Prob. 36PPCh. 5 - Prob. 37PPCh. 5 - Prob. 38PPCh. 5 - Prob. 39PPCh. 5 - Prob. 40PPCh. 5 - Prob. 41PPCh. 5 - Prob. 42PPCh. 5 - Prob. 43PPCh. 5 - Prob. 44PPCh. 5 - Prob. 45PPCh. 5 - Prob. 46PPCh. 5 - Prob. 47PPCh. 5 - Prob. 48PPCh. 5 - Prob. 49PPCh. 5 - Prob. 50PPCh. 5 - Prob. 51PPCh. 5 - Prob. 52PPCh. 5 - Prob. 53IPCh. 5 - Prob. 54IPCh. 5 - Prob. 55IPCh. 5 - Prob. 56IPCh. 5 - Prob. 57IPCh. 5 - Prob. 58IPCh. 5 - Prob. 59IPCh. 5 - Prob. 60IPCh. 5 - Prob. 61IPCh. 5 - Prob. 62IPCh. 5 - Prob. 63IPCh. 5 - Prob. 64IPCh. 5 - Prob. 65IP
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