Program Explanation Given information: The matrix differential equation for the given system is shown below. x ″ = [ − c 1 c 1 c 2 − c 2 ] x Here coefficient c i is defined as, c i = k m i The value of mass m 1 and mass m 2 for the given system is written below. m 1 = 500 slugs m 2 = 1000 slugs The value of spring constant is written as, k = 3000 lb / ft The initial conditions for the system are written as, x 1 ( 0 ) = 0 , x 2 ( 0 ) = 0 x ′ 1 ( 0 ) = v 0 , x ′ 2 ( 0 ) = 0 Explanation: The matrix differential equation for the given system is written as, x ″ = [ − c 1 c 1 c 2 − c 2 ] x The matrix A for the system is written below. A = [ − c 1 c 1 c 2 − c 2 ] A = [ − k m 1 k m 1 k m 2 − k m 2 ] Substitute the corresponding values from the given information and write as, A = [ − 6 6 3 − 3 ] So, obtain the characteristic equation of matrix A to obtain the eigenvalues as, | − 6 − λ 6 3 − 3 − λ | = 0 ( − 6 − λ ) ( − 3 − λ ) − 18 = 0 λ 2 + 9 λ + 18 − 18 = 0 λ 2 + 9 λ = 0 Further, solve the above equation as, λ ( λ + 9 ) = 0 λ 1 = 0 or λ 2 = − 9 Now, obtain the eigenvector corresponding to λ 1 = 0 as follows: [ − 6 − 0 6 3 − 3 − 0 ] [ a b ] = [ 0 0 ] [ − 6 6 3 − 3 ] [ a b ] = [ 0 0 ] [ − 6 a + 6 b 3 a − 3 b ] = [ 0 0 ] From the comparison of corresponding elements from both sides and simplification, it is obtained that b = a . For simplest vector, consider 1 for a , and therefore b = 1 , and the eigenvector corresponding to λ 1 = 0 is written as, v 1 = [ 1 1 ] Similarly, obtain the eigenvector corresponding to λ 2 = − 9 as follows: [ − 6 − ( − 9 ) 6 3 − 3 − ( − 9 ) ] [ a b ] = [ 0 0 ] [ 3 6 3 6 ] [ a b ] = [ 0 0 ] [ 3 a + 6 b 3 a + 6 b ] = [ 0 0 ] From the comparison of corresponding elements from both sides and simplification, it is obtained that a = − 2 b

5th Edition

ISBN: 9780135988510

Author: Edwards

Publisher: PEARSON CO

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A naïve solution for the above-stated problem is to evaluate all of the possible combinations of different pieces of varying size to find the maximum revenue-generating combination. Although this method seems the easiest and quick to practice, it has exp…

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Chapter 5.4, Problem 18P

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Program Description: Purpose of the problem is to show that the cars separate after π/3 seconds and rebound in opposite directions.

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Chapter 5.4, Problem 17P

Chapter 5.4, Problem 19P

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Chapter 5 Solutions

EP DIFF.EQUAT.+BOUND.VALUE,...UPD.-ACC.

Ch. 5.1 - Let A=[2347] and B=[3451]. Find (a) 2A+3B; (b)...Ch. 5.1 - Prob. 2P Ch. 5.1 - Find AB and BA given A=[203415] and B=[137032].Ch. 5.1 - Prob. 4P Ch. 5.1 - Prob. 5P Ch. 5.1 - Prob. 6P Ch. 5.1 - Prob. 7P Ch. 5.1 - Prob. 8P Ch. 5.1 - Prob. 9P Ch. 5.1 - Prob. 10P

Ch. 5.1 - Prob. 11P Ch. 5.1 - Prob. 12P Ch. 5.1 - Prob. 13P Ch. 5.1 - Prob. 14P Ch. 5.1 - Prob. 15P Ch. 5.1 - Prob. 16P Ch. 5.1 - Prob. 17P Ch. 5.1 - Prob. 18P Ch. 5.1 - Prob. 19P Ch. 5.1 - Prob. 20P Ch. 5.1 - Prob. 21P Ch. 5.1 - Prob. 22P Ch. 5.1 - Prob. 23P Ch. 5.1 - Prob. 24P Ch. 5.1 - Prob. 25P Ch. 5.1 - Prob. 26P Ch. 5.1 - Prob. 27P Ch. 5.1 - Prob. 28P Ch. 5.1 - Prob. 29P Ch. 5.1 - Prob. 30P Ch. 5.1 - Prob. 31P Ch. 5.1 - Prob. 32P Ch. 5.1 - Prob. 33P Ch. 5.1 - Prob. 34P Ch. 5.1 - Prob. 35P Ch. 5.1 - Prob. 36P Ch. 5.1 - Prob. 37P Ch. 5.1 - Prob. 38P Ch. 5.1 - Prob. 39P Ch. 5.1 - Prob. 40P Ch. 5.1 - Prob. 41P Ch. 5.1 - Prob. 42P Ch. 5.1 - Prob. 43P Ch. 5.1 - Prob. 44P Ch. 5.1 - Prob. 45P Ch. 5.2 - Prob. 1P Ch. 5.2 - Prob. 2P Ch. 5.2 - Prob. 3P Ch. 5.2 - Prob. 4P Ch. 5.2 - Prob. 5P Ch. 5.2 - Prob. 6P Ch. 5.2 - Prob. 7P Ch. 5.2 - Prob. 8P Ch. 5.2 - Prob. 9P Ch. 5.2 - Prob. 10P Ch. 5.2 - Prob. 11P Ch. 5.2 - Prob. 12P Ch. 5.2 - Prob. 13P Ch. 5.2 - Prob. 14P Ch. 5.2 - Prob. 15P Ch. 5.2 - Prob. 16P Ch. 5.2 - Prob. 17P Ch. 5.2 - Prob. 18P Ch. 5.2 - Prob. 19P Ch. 5.2 - Prob. 20P Ch. 5.2 - Prob. 21P Ch. 5.2 - Prob. 22P Ch. 5.2 - Prob. 23P Ch. 5.2 - Prob. 24P Ch. 5.2 - Prob. 25P Ch. 5.2 - Prob. 26P Ch. 5.2 - Prob. 27P Ch. 5.2 - Prob. 28P Ch. 5.2 - Prob. 29P Ch. 5.2 - Prob. 30P Ch. 5.2 - Prob. 31P Ch. 5.2 - Prob. 32P Ch. 5.2 - Prob. 33P Ch. 5.2 - Prob. 34P Ch. 5.2 - Prob. 35P Ch. 5.2 - Prob. 36P Ch. 5.2 - Prob. 37P Ch. 5.2 - Prob. 38P Ch. 5.2 - Prob. 39P Ch. 5.2 - Prob. 40P Ch. 5.2 - Prob. 41P Ch. 5.2 - Prob. 42P Ch. 5.2 - Prob. 43P Ch. 5.2 - Prob. 44P Ch. 5.2 - Prob. 45P Ch. 5.2 - Prob. 46P Ch. 5.2 - Prob. 47P Ch. 5.2 - Prob. 48P Ch. 5.2 - Prob. 49P Ch. 5.2 - Prob. 50P Ch. 5.3 - Prob. 1P Ch. 5.3 - Prob. 2P Ch. 5.3 - Prob. 3P Ch. 5.3 - Prob. 4P Ch. 5.3 - Prob. 5P Ch. 5.3 - Prob. 6P Ch. 5.3 - Prob. 7P Ch. 5.3 - Prob. 8P Ch. 5.3 - Prob. 9P Ch. 5.3 - Prob. 10P Ch. 5.3 - Prob. 11P Ch. 5.3 - Prob. 12P Ch. 5.3 - Prob. 13P Ch. 5.3 - Prob. 14P Ch. 5.3 - Prob. 15P Ch. 5.3 - Prob. 16P Ch. 5.3 - Prob. 17P Ch. 5.3 - Prob. 18P Ch. 5.3 - Prob. 19P Ch. 5.3 - Prob. 20P Ch. 5.3 - Prob. 21P Ch. 5.3 - Prob. 22P Ch. 5.3 - Prob. 23P Ch. 5.3 - Prob. 24P Ch. 5.3 - Prob. 25P Ch. 5.3 - Prob. 26P Ch. 5.3 - Prob. 27P Ch. 5.3 - Prob. 28P Ch. 5.3 - Prob. 29P Ch. 5.3 - Prob. 30P Ch. 5.3 - Prob. 31P Ch. 5.3 - Prob. 32P Ch. 5.3 - Prob. 33P Ch. 5.3 - Verify Eq. 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Program Description: Purpose of the problem is to show that the cars separate after π / 3 seconds and rebound in opposite directions.

Solution Summary: The author explains the purpose of the problem, which is to show that the cars separate after pi /3 seconds and rebound in opposite directions.

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Program Description: Purpose of the problem is to show that the cars separate after π/3 seconds and rebound in opposite directions.

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Chapter 5 Solutions