Organic Chemistry
3rd Edition
ISBN: 9781119338352
Author: Klein
Publisher: WILEY
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Chapter 5.4, Problem 15PTS
Interpretation Introduction
Interpretation:
To calculate the enantiomeric excess (ee) of given molecules.
Concept Introduction:
Enantiomeric excess: The (ee) is a measurement of purity for chiral substances, and its reflected the degree to which a sample contains one enantiomer in greater amounts then the other.
Consider for simple example the d-enantiomers (75%) exceeds the percentage of the l-enantiomers (25%) and (ee) of compound 50%.
To identify: The given molecules enantiomeric excess (ee) should be identified.
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Students have asked these similar questions
LTS
Solid:
AT=Te-Ti
Trial 1
Trial 2
Trial 3
Average
ΔΗ
Mass water, g
24.096
23.976
23.975
Moles of solid, mol
0.01763
001767
0101781
Temp. change, °C
2.9°C
11700
2.0°C
Heat of reaction, J
-292.37J -170.473
-193.26J
AH, kJ/mole
16.58K 9.647 kJ 10.85 kr
16.58K59.64701
KJ
mol
12.35k
Minimum AS,
J/mol K
41.582
mol-k
Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn &
Show your calculations for:
AH in J and then in kJ/mole for Trial 1:
qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J
qsin =
qrxn =
292.35 292.37J
AH in J = 292.375 0.2923kJ
0.01763m01
=1.65×107
AH in kJ/mol =
=
16.58K
0.01763mol
mol
qrx
Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con
Kelvin.)
AS=AHIT
(1.65×10(9.64×103) + (1.0
Jimai
For the compound: C8H17NO2
Use the following information to come up with a plausible structure:
8
This compound has "carboxylic acid amide" and ether functional groups.
The peaks at 1.2ppm are two signals that are overlapping one another.
One of the two signals is a doublet that represents 6 hydrogens; the
other signal is a quartet that represents 3 hydrogens.
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Chapter 5 Solutions
Organic Chemistry
Ch. 5.1 -
In the following compound, identify each unit...Ch. 5.1 - Prob. 2CCCh. 5.1 - Prob. 3CCCh. 5.2 - Prob. 1LTSCh. 5.2 - Prob. 4PTSCh. 5.2 - Prob. 5ATSCh. 5.2 - Prob. 6ATSCh. 5.2 - Prob. 2LTSCh. 5.2 - Prob. 7PTSCh. 5.2 - Prob. 8ATS
Ch. 5.3 - Prob. 3LTSCh. 5.3 - Prob. 9PTSCh. 5.3 - Prob. 10ATSCh. 5.4 - Prob. 4LTSCh. 5.4 - Prob. 11PTSCh. 5.4 - Prob. 12PTSCh. 5.4 - Prob. 13PTSCh. 5.4 - Prob. 14ATSCh. 5.4 - Prob. 5LTSCh. 5.4 - Prob. 15PTSCh. 5.4 - Prob. 16PTSCh. 5.4 - Prob. 17PTSCh. 5.4 - Prob. 18ATSCh. 5.5 - Prob. 6LTSCh. 5.5 - Prob. 19PTSCh. 5.5 - Prob. 20ATSCh. 5.6 - Prob. 21CCCh. 5.6 - Prob. 22CCCh. 5.6 - Prob. 23CCCh. 5.6 - Prob. 7LTSCh. 5.6 - Prob. 24PTSCh. 5.6 - Prob. 25ATSCh. 5.7 - Prob. 8LTSCh. 5.7 - Prob. 26PTSCh. 5.7 -
Protease inhibitors are a class of anti-viral...Ch. 5.9 - Prob. 28CCCh. 5.11 - Prob. 9LTSCh. 5.11 - Prob. 29PTSCh. 5.11 - Prob. 30ATSCh. 5 - Prob. 31PPCh. 5 - Prob. 32PPCh. 5 - Prob. 33PPCh. 5 - Prob. 34PPCh. 5 - Prob. 35PPCh. 5 - Prob. 36PPCh. 5 - Prob. 37PPCh. 5 - Prob. 38PPCh. 5 - Prob. 39PPCh. 5 - Prob. 40PPCh. 5 - Prob. 41PPCh. 5 - Prob. 42PPCh. 5 - Prob. 43PPCh. 5 - Prob. 44PPCh. 5 - Prob. 45PPCh. 5 - Prob. 46PPCh. 5 - Prob. 47PPCh. 5 - Prob. 48PPCh. 5 - Prob. 49PPCh. 5 - Prob. 50PPCh. 5 - Prob. 51PPCh. 5 - Prob. 52PPCh. 5 - For each of the following pairs of compounds,...Ch. 5 - Prob. 54PPCh. 5 - Prob. 55PPCh. 5 - Prob. 56PPCh. 5 - Prob. 57IPCh. 5 - Prob. 58IPCh. 5 - Prob. 59IPCh. 5 - Prob. 60IPCh. 5 - There are only two stereoisomers of...Ch. 5 - Prob. 62IPCh. 5 - Prob. 63IPCh. 5 - Prob. 64IPCh. 5 - Prob. 65IPCh. 5 - Prob. 66IPCh. 5 - Prob. 67IPCh. 5 - Prob. 68IPCh. 5 - Prob. 69IPCh. 5 - Prob. 70IPCh. 5 - Prob. 71IPCh. 5 - Prob. 72IPCh. 5 - Prob. 73IPCh. 5 - Prob. 74IPCh. 5 - Prob. 75IPCh. 5 - Prob. 76IPCh. 5 - Prob. 77CPCh. 5 - Prob. 78CPCh. 5 - Prob. 79CPCh. 5 - Prob. 80CP
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