EBK INTRODUCTION TO THE PRACTICE OF STA
EBK INTRODUCTION TO THE PRACTICE OF STA
9th Edition
ISBN: 8220103674638
Author: Moore
Publisher: YUZU
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 5.3, Problem 69E

(a)

To determine

The values of n and p for X, which is binomially distributed.

(a)

Expert Solution
Check Mark

Answer to Problem 69E

Solution: The required distribution of X is p=0.62 and n=4_.

Explanation of Solution

It is provided that 62% of the selected people admitted that they had received nasty messages on social sites. So, the probability of success for this case is p=0.62. The total number of people, which is 4, is randomly selected, so the total number of trails n=4. Assume X of them admitted that they had received nasty messages. Here X is binomially distributed with parameters p=0.62 and n=4. So, the required distribution of X is p=0.62 and n=4.

(b)

To determine

To find: The probability of every possible value of X.

(b)

Expert Solution
Check Mark

Answer to Problem 69E

Solution: Probability distribution for each value of X is:

X

P(X)

0

0.02085

1

0.1360

2

0.333

3

0.3622

4

0.1477

Explanation of Solution

Calculation: In the provided problem the distribution can be calculated as:

P(X)=(nX)P(1P)X1

For X=0.

P(0)=(40)(0.62)(10.62)4=(40)(0.62)(0.38)4=0.02085

For X=1.

P(1)=(41)(0.62)(10.62)3=(41)(0.62)(0.38)3=0.1360

For X=2.

P(2)=(42)(0.62)(10.62)2=(42)(0.62)(0.38)2=0.333

For X=3.

P(3)=(43)(0.62)(10.62)1=(43)(0.62)(0.38)1=0.3622

For X=4.

P(4)=(44)(0.62)(10.62)0=(44)(0.62)(0.38)0=0.1477

Hence, the table representing every possible value of X and the probability parallel to X is shown below:

X

P(X)

0

0.02085

1

0.1360

2

0.333

3

0.3622

4

0.1477

To determine

To graph: A probability histogram for the obtained distribution.

Expert Solution
Check Mark

Explanation of Solution

Graph: In the provided problem, the distribution of X is obtained in the part above. Now, the probability histogram can be obtained by using Minitab. The steps to be followed are enlisted below:

Step 1: Input the values of X and the probability in Minitab worksheet.

Step 2: Go to Graph > Histogram.

Step 3: Choose ‘View simple’ and click OK.

Step 4: Insert the value of X and the probability p in the column of graph variables.

Step 5: Click on Ok.

The Histogram is obtained as:

EBK INTRODUCTION TO THE PRACTICE OF STA, Chapter 5.3, Problem 69E , additional homework tip  1

The probability histogram is obtained for the required distribution of X.

(c)

To determine

To Find: The average number of responders who said yes.

(c)

Expert Solution
Check Mark

Answer to Problem 69E

Solution: The required average is 2.48.

Explanation of Solution

Calculation: Binomial mean can be calculated using this formula,

μx=np

Substitute the values p=0.62 and n=4 in the formula above to obtain the mean. Mean can be calculated as:

μx=np=4(0.62)=2.48

The required average is 2.48.

To determine

To graph: The average value in the obtained histogram.

Expert Solution
Check Mark

Explanation of Solution

Graph: The obtained average value is 2.48. To mark this value in the obtained histogram, the steps are as follows:

Step 1: Go to the histogram which is obtained above.

Step 2: Double click on the X axis.

Step 3: Select ‘Position of ticks’ and enter the obtained mean value 2.48.

Step 4: Click on Ok.

The histogram obtained is:

EBK INTRODUCTION TO THE PRACTICE OF STA, Chapter 5.3, Problem 69E , additional homework tip  2

The histogram with the mark of mean value 2.48 is obtained.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Find binomial probability if: x = 8, n = 10, p = 0.7 x= 3, n=5, p = 0.3 x = 4, n=7, p = 0.6 Quality Control: A factory produces light bulbs with a 2% defect rate. If a random sample of 20 bulbs is tested, what is the probability that exactly 2 bulbs are defective? (hint: p=2% or 0.02; x =2, n=20; use the same logic for the following problems) Marketing Campaign: A marketing company sends out 1,000 promotional emails. The probability of any email being opened is 0.15. What is the probability that exactly 150 emails will be opened? (hint: total emails or n=1000, x =150) Customer Satisfaction: A survey shows that 70% of customers are satisfied with a new product. Out of 10 randomly selected customers, what is the probability that at least 8 are satisfied? (hint: One of the keyword in this question is “at least 8”, it is not “exactly 8”, the correct formula for this should be = 1- (binom.dist(7, 10, 0.7, TRUE)). The part in the princess will give you the probability of seven and less than…
please answer these questions
Selon une économiste d’une société financière, les dépenses moyennes pour « meubles et appareils de maison » ont été moins importantes pour les ménages de la région de Montréal, que celles de la région de Québec. Un échantillon aléatoire de 14 ménages pour la région de Montréal et de 16 ménages pour la région Québec est tiré et donne les données suivantes, en ce qui a trait aux dépenses pour ce secteur d’activité économique. On suppose que les données de chaque population sont distribuées selon une loi normale. Nous sommes intéressé à connaitre si les variances des populations sont égales.a)    Faites le test d’hypothèse sur deux variances approprié au seuil de signification de 1 %. Inclure les informations suivantes : i.    Hypothèse / Identification des populationsii.    Valeur(s) critique(s) de Fiii.    Règle de décisioniv.    Valeur du rapport Fv.    Décision et conclusion b)    A partir des résultats obtenus en a), est-ce que l’hypothèse d’égalité des variances pour cette…

Chapter 5 Solutions

EBK INTRODUCTION TO THE PRACTICE OF STA

Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.2 - Prob. 17UYKCh. 5.2 - Prob. 18UYKCh. 5.2 - Prob. 19UYKCh. 5.2 - Prob. 20UYKCh. 5.2 - Prob. 21UYKCh. 5.2 - Prob. 22UYKCh. 5.2 - Prob. 23UYKCh. 5.2 - Prob. 24UYKCh. 5.2 - Prob. 25ECh. 5.2 - Prob. 26ECh. 5.2 - Prob. 27ECh. 5.2 - Prob. 28ECh. 5.2 - Prob. 29ECh. 5.2 - Prob. 30ECh. 5.2 - Prob. 31ECh. 5.2 - Prob. 32ECh. 5.2 - Prob. 33ECh. 5.2 - Prob. 34ECh. 5.2 - Prob. 35ECh. 5.2 - Prob. 36ECh. 5.2 - Prob. 37ECh. 5.2 - Prob. 38ECh. 5.2 - Prob. 39ECh. 5.2 - Prob. 40ECh. 5.2 - Prob. 41ECh. 5.2 - Prob. 42ECh. 5.3 - Prob. 43UYKCh. 5.3 - Prob. 44UYKCh. 5.3 - Prob. 45UYKCh. 5.3 - Prob. 46UYKCh. 5.3 - Prob. 47UYKCh. 5.3 - Prob. 48UYKCh. 5.3 - Prob. 49UYKCh. 5.3 - Prob. 50UYKCh. 5.3 - Prob. 51UYKCh. 5.3 - Prob. 52UYKCh. 5.3 - Prob. 53UYKCh. 5.3 - Prob. 54UYKCh. 5.3 - Prob. 55UYKCh. 5.3 - Prob. 56UYKCh. 5.3 - Prob. 57ECh. 5.3 - Prob. 58ECh. 5.3 - Prob. 59ECh. 5.3 - Prob. 60ECh. 5.3 - Prob. 61ECh. 5.3 - Prob. 62ECh. 5.3 - Prob. 63ECh. 5.3 - Prob. 64ECh. 5.3 - Prob. 65ECh. 5.3 - Prob. 66ECh. 5.3 - Prob. 67ECh. 5.3 - Prob. 68ECh. 5.3 - Prob. 69ECh. 5.3 - Prob. 70ECh. 5.3 - Prob. 71ECh. 5.3 - Prob. 72ECh. 5.3 - Prob. 73ECh. 5.3 - Prob. 74ECh. 5.3 - Prob. 75ECh. 5.3 - Prob. 76ECh. 5.3 - Prob. 77ECh. 5.3 - Prob. 78ECh. 5.3 - Prob. 79ECh. 5.3 - Prob. 80ECh. 5.3 - Prob. 81ECh. 5.3 - Prob. 82ECh. 5.3 - Prob. 83ECh. 5 - Prob. 84ECh. 5 - Prob. 85ECh. 5 - Prob. 86ECh. 5 - Prob. 87ECh. 5 - Prob. 88ECh. 5 - Prob. 89ECh. 5 - Prob. 90ECh. 5 - Prob. 91ECh. 5 - Prob. 92ECh. 5 - Prob. 93ECh. 5 - Prob. 94ECh. 5 - Prob. 95ECh. 5 - Prob. 96ECh. 5 - Prob. 97ECh. 5 - Prob. 98ECh. 5 - Prob. 99ECh. 5 - Prob. 100ECh. 5 - Prob. 101ECh. 5 - Prob. 102E
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Text book image
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Text book image
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Text book image
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
Text book image
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Text book image
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman
Probability & Statistics (28 of 62) Basic Definitions and Symbols Summarized; Author: Michel van Biezen;https://www.youtube.com/watch?v=21V9WBJLAL8;License: Standard YouTube License, CC-BY
Introduction to Probability, Basic Overview - Sample Space, & Tree Diagrams; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=SkidyDQuupA;License: Standard YouTube License, CC-BY