In Problem 1-8, if necessary, review Theorem 1. In Problems 1-4, the feasible region is the set of points on and inside the rectangle with vertices 0 , 0 , 12 , 0 , 0 , 5 , and 12 , 5 . Find the maximum and minimum values of the objective function Q over the feasible region. Q = − 9 x + 20 y
In Problem 1-8, if necessary, review Theorem 1. In Problems 1-4, the feasible region is the set of points on and inside the rectangle with vertices 0 , 0 , 12 , 0 , 0 , 5 , and 12 , 5 . Find the maximum and minimum values of the objective function Q over the feasible region. Q = − 9 x + 20 y
Solution Summary: The author calculates the maximum and minimum values of the objective function Q=-9x+20y over the feasible region, based on the Fundamental Theorem of Linear Programming.
In Problem 1-8, if necessary, review Theorem 1. In Problems 1-4, the feasible region is the set of points on and inside the rectangle with vertices
0
,
0
,
12
,
0
,
0
,
5
, and
12
,
5
. Find the maximum and minimum values of the objective function
Q
over the feasible region.
A function is defined on the interval (-π/2,π/2) by this multipart rule:
if -π/2 < x < 0
f(x) =
a
if x=0
31-tan x
+31-cot x
if 0 < x < π/2
Here, a and b are constants. Find a and b so that the function f(x) is continuous at x=0.
a=
b= 3
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a.
f(x) = (x + 4x4) 5,
a = -1
lim f(x)
X--1
=
lim
x+4x
X--1
lim
X-1
4
x+4x
5
))"
5
))
by the power law
by the sum law
lim (x) + lim
X--1
4
4x
X-1
-(0,00+(
Find f(-1).
f(-1)=243
lim (x) +
-1 +4
35
4 ([
)
lim (x4)
5
x-1
Thus, by the definition of continuity, f is continuous at a = -1.
by the multiple constant law
by the direct substitution property
Chapter 5 Solutions
Finite Mathematics for Business, Economics, Life Sciences, and Social Sciences (13th Edition)
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