The possibilities of obtaining a beardless male offspring in a cross between two bearded goats. Introduction: In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele B b is responsible for the beard and allele B + is responsible for beardless phenotype . In males, B b allele is dominant over B + . In females, recessive allele is responsible for beard.

Question

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Answer 1

Question

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

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Answer 2

Question

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

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Answer 3

Question

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

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Answer 4

Question

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

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Answer 5

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

Answer 6

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Answer 7

Chapter 5.3, Problem 3TPSQ

Summary Introduction

To determine:

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, presence of beard is a sex influenced character, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. In males, $Bb$ allele is dominant over $B+$ . In females, recessive allele is responsible for beard.

Answer 8

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats:

If the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother is $0%$

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Answer 13

Summary Introduction

To determine:

The reason why or why not it is possible to obtain a beardless male offspring in a cross between two bearded goats.

Introduction:

In goats, phenotype for beard is determined by the genotypes: $B+B+$ is responsible for beardless male and female, $B+Bb$ is responsible for breaded male and beardless female, and $BbBb$ is responsible for bearded male and female.

Answer 14

Expert Solution

Explanation of Solution

Beard in goats is a sex influenced phenotype, as male and female have different genotypes. Allele $Bb$ is responsible for the beard and allele $B+$ is responsible for beardless phenotype. $Bb$ allele is dominant over $B+$ . In males, the presence of dominant allele is responsible for the occurrence of beard whereas in females, occurrence of recessive allele is responsible for beard.

Hence, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$B+Bb$

(Bearded male)

$BbBb$

(Bearded male)

If the parent goats have genotype $BbBb$ for father and $BbBb$ for mother, all male progenies produced are beardless.

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

$Bb$

$BbBb$

(Bearded male)

$BbBb$

(Bearded male)

Answer 15

Expert Solution

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

Answer 19

Summary Introduction

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction:

Answer 20

Expert Solution

Explanation of Solution

Genotypes responsible for beard and beardless phenotype in goats are given in the following table:

Genotype	Males	Females
$B+B+$	Beardless	Beardless
$B+Bb$	Bearded	Beardless
$BbBb$	Bearded	Bearded

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats:

If the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother

$B+Bb × BbBb ↓$

$B+$

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

$Bb$

$B+Bb$

(Beardless female)

$BbBb$

(Beardless female)

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype $B+Bb$ for father and $BbBb$ for mother is $50%$

If the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother:

$BbBb × BbBb ↓$

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

$Bb$

$BbBb$

(Bearded female)

$BbBb$

(Bearded female)

The possibilities of obtaining a bearded male offspring in a cross between two bearded goats, if the parent goats have genotype $BbBb$ for father and $BbBb$ for mother is $100%$

Answer 21

Expert Solution

Answer 22

Expert Solution

Answer 23

Expert Solution

Answer 24

Conclusion

The possibilities of obtaining a beardless male offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $0%$ , and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $0%$ . The possibilities of obtaining a bearded female offspring in a cross between two bearded goats, if the parent goats have genotype: $B+Bb$ for father and $BbBb$ for mother is $50%$ ,and if the parent goats have genotype: $BbBb$ for father and $BbBb$ for mother, it is $100%$

Answer 25

Ch. 5.1 - Prob. 1CC Ch. 5.1 - Prob. 2CC Ch. 5.1 - Prob. 3CC Ch. 5.1 - Prob. 4CC Ch. 5.1 - Prob. 5CC Ch. 5.1 - Prob. 1COQ Ch. 5.1 - Prob. 2COQ Ch. 5.1 - Prob. 13AQP Ch. 5.1 - Prob. 14AQP Ch. 5.1 - Prob. 15AQP

Explanation of Solution

Explanation of Solution

To determine: The possibilities of obtaining a bearded female offspring in a cross between two bearded goats. Introduction:

Explanation of Solution

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Chapter 5 Solutions

To determine:

The possibilities of obtaining a bearded female offspring in a cross between two bearded goats.

Introduction: