EBK PRE-ALGEBRA
EBK PRE-ALGEBRA
12th Edition
ISBN: 9780358403685
Author: Larson
Publisher: HM CC
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Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
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Question
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Chapter 5.2, Problem 7C
To determine

To find: The sum or difference.

Expert Solution & Answer
Check Mark

Answer to Problem 7C

The difference of the equation 415−235 is 85.

Explanation of Solution

Given information: 415−235.

Calculation:

Converting from mixed fraction to improper fraction,

=415=(5×4)+15=20+15=215......(1)

=235=(5×2)+35=10+35=135......(2)

Since, 215 is a positive number, and 135 is a negative.

Let’s finding the difference of the fraction (1) and (2),

=215−135=21−135=85 , Taking 15 as the LCM (Least common multiple)

Hence, The difference of the equation 415−235 is 85 .

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Chapter 5.2, Problem 6C
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Chapter 5.2, Problem 8C

Chapter 5 Solutions

EBK PRE-ALGEBRA

Ch. 5.1 - Prob. 1CCh. 5.1 - Prob. 2CCh. 5.1 - Prob. 3CCh. 5.1 - Prob. 4CCh. 5.1 - Prob. 5CCh. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5E
Ch. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10ECh. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.1 - Prob. 31ECh. 5.1 - Prob. 32ECh. 5.1 - Prob. 33ECh. 5.1 - Prob. 34ECh. 5.1 - Prob. 35ECh. 5.1 - Prob. 36ECh. 5.1 - Prob. 37ECh. 5.1 - Prob. 38ECh. 5.1 - Prob. 39ECh. 5.1 - Prob. 40ECh. 5.1 - Prob. 41ECh. 5.1 - Prob. 42ECh. 5.1 - Prob. 43ECh. 5.1 - Prob. 44ECh. 5.1 - Prob. 45ECh. 5.1 - Prob. 46ECh. 5.1 - Prob. 47ECh. 5.1 - Prob. 48ECh. 5.1 - Prob. 49ECh. 5.1 - Prob. 50ECh. 5.1 - Prob. 51ECh. 5.1 - Prob. 52ECh. 5.1 - Prob. 53ECh. 5.1 - Prob. 54ECh. 5.1 - Prob. 55ECh. 5.1 - Prob. 56ECh. 5.1 - Prob. 57ECh. 5.1 - Prob. 58ECh. 5.1 - 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Prob. 48ECh. 5.7 - Prob. 49ECh. 5.7 - Prob. 50ECh. 5.7 - Prob. 51ECh. 5.7 - Prob. 52ECh. 5.7 - Prob. 53ECh. 5.7 - Prob. 54ECh. 5.7 - Prob. 55ECh. 5.7 - Prob. 56ECh. 5.7 - Prob. 57ECh. 5 - Prob. 1PSQCh. 5 - Prob. 2PSQCh. 5 - Prob. 3PSQCh. 5 - Prob. 4PSQCh. 5 - Prob. 5PSQCh. 5 - Prob. 6PSQCh. 5 - Prob. 7PSQCh. 5 - Prob. 8PSQCh. 5 - Prob. 9PSQCh. 5 - Prob. 10PSQCh. 5 - Prob. 11PSQCh. 5 - Prob. 12PSQCh. 5 - Prob. 13PSQCh. 5 - Prob. 14PSQCh. 5 - Prob. 15PSQCh. 5 - Prob. 16PSQCh. 5 - Prob. 17PSQCh. 5 - Prob. 1MCQCh. 5 - Prob. 2MCQCh. 5 - Prob. 3MCQCh. 5 - Prob. 4MCQCh. 5 - Prob. 5MCQCh. 5 - Prob. 6MCQCh. 5 - Prob. 7MCQCh. 5 - Prob. 8MCQCh. 5 - Prob. 9MCQCh. 5 - Prob. 10MCQCh. 5 - Prob. 11MCQCh. 5 - Prob. 12MCQCh. 5 - Prob. 13MCQCh. 5 - Prob. 14MCQCh. 5 - Prob. 15MCQCh. 5 - Prob. 16MCQCh. 5 - Prob. 17MCQCh. 5 - Prob. 18MCQCh. 5 - Prob. 19MCQCh. 5 - Prob. 20MCQCh. 5 - Prob. 21MCQCh. 5 - Prob. 22MCQCh. 5 - Prob. 23MCQCh. 5 - Prob. 24MCQCh. 5 - Prob. 25MCQCh. 5 - Prob. 1CRCh. 5 - Prob. 2CRCh. 5 - 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