Explanation Formula used: ∫ e − x d x = − e − x + C (1) Calculation: The given integral is ∫ e − 0.001 x d x . Use formula (1) and obtain the indefinite integral ∫ e − 0.001 x d x . Apply u substitution as u = − 0.001 x . Differentiate u = − 0.001 x with respect to x. u = − 0.001 x d u = − 0.001 d x d x = − 1 0.001 d u Substitute u = − 0.001 x and d x = − 1 0.001 d u in ∫ e − 0.001 x d x , ∫ e − 0.001 x d x = ∫ e u − 1 0.001 d u = − 1 0.001 ∫ e u d u = − 1 0.001 e u + C Substitute u = − 0.001 x in ∫ e − 0.001 x d x = − 1 0.001 e u + C , ∫ e − 0

Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

14th Edition

ISBN: 9780134668574

Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen, Christopher J. Stocker

Publisher: PEARSON

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Chapter 5.2, Problem 28E

To determine

To find: The value of the indefinite integral ∫e−0.001xdx and check the obtained value by differentiation.

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Chapter 5.2, Problem 27E

Chapter 5.2, Problem 29E

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Chapter 5 Solutions

Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

Ch. 5.1 - Matched Problem 1 Note that ddx(x3)=3x2 A. Find...Ch. 5.1 - Find each indefinite integral: (A) 2dx (B) 16etdt...Ch. 5.1 - Matched Problem 3 Find each indefinite integral:...Ch. 5.1 - Matched Problem 4 Find the equation of the curve...Ch. 5.1 - Matched Problem 5 Find the revenue function R(x)...Ch. 5.1 - Matched Problem 6 There are currently 64,000...Ch. 5.1 - Explore and Discuss 1 Formulas 1, 2, and 3 do not...Ch. 5.1 - In Problems 18, write each function as a sum of...Ch. 5.1 - In Problems 18, write each function as a sum of...Ch. 5.1 - In Problems 18, write each function as a sum of...

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The value of the indefinite integral ∫ e − 0.001 x d x and check the obtained value by differentiation.

To find: The value of the indefinite integral ∫e−0.001xdx and check the obtained value by differentiation.

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Chapter 5 Solutions