ORGANIC CHEMISTRY BOOK& SG/SM
ORGANIC CHEMISTRY BOOK& SG/SM
6th Edition
ISBN: 9781264094493
Author: SMITH
Publisher: MCG
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Chapter 5.12, Problem 34P

(a)

Interpretation Introduction

Interpretation:

The percent of each enantiomer present for the given value needs to be calculated:

90% ee

Concept Introduction :

If one enantiomer dominates the other in a mixture of two, the excess of that enantiomer is then stated as a percentage of the total amount of that enantiomer. It also gives some information about the mixture's overall optical rotation.

(b)

Interpretation Introduction

Interpretation:

The percent of each enantiomer present for the given value needs to be calculated:

99%ee

Concept Introduction :

If one enantiomer dominates the other in a mixture of two, the excess of that enantiomer is then stated as a percentage of the total amount of that enantiomer. It also gives some information about the mixture's overall optical rotation.

(c)

Interpretation Introduction

Interpretation:

The percent of each enantiomer present for the given value needs to be calculated:

60%ee

Concept Introduction :

If one enantiomer dominates the other in a mixture of two, the excess of that enantiomer is then stated as a percentage of the total amount of that enantiomer. It also gives some information about the mixture's overall optical rotation.

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Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0
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