ORGANIC CHEMISTRY BOOK& SG/SM
ORGANIC CHEMISTRY BOOK& SG/SM
6th Edition
ISBN: 9781264094493
Author: SMITH
Publisher: MCG
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Chapter 5, Problem 39P
Interpretation Introduction

(a)

Interpretation: The stereogenic centers in the ball-and-stick model of ezetimibe are to be located.

Concept introduction: A carbon atom that has four nonequivalent atoms or groups attached to it is known as chiral carbon atom. Chiral carbon centers are also called as asymmetric or stereogenic centers.

Expert Solution
Check Mark

Answer to Problem 39P

The stereogenic centers in ezetimibe are,

ORGANIC CHEMISTRY BOOK& SG/SM, Chapter 5, Problem 39P , additional homework tip  1

Explanation of Solution

The given ball-and-stick model of ezetimibe is shown below.

ORGANIC CHEMISTRY BOOK& SG/SM, Chapter 5, Problem 39P , additional homework tip  2

Figure 1

In the ball-and-stick model of ezetimibe, yellow balls represent halogen atom as they contain one covalent bond. Black balls are bonded to each other through four covalent bonds, thus; they represent carbon atom. Red balls represent oxygen atom as they contain two covalent bonds and blue balls represent nitrogen atom because they contain three covalent bonds.

The stereogenic center is one that has four different groups attached to carbon atom tetrahedrally. The stereogenic centers in the given molecule are located by omitting all CH2 and CH3 groups and all sp2 hybridized carbon atoms. The stereogenic centers in ezetimibe are shown below which are marked by asterisk. For easy reference, the ball-and-stick model of ezetimibe is represented as follows,

ORGANIC CHEMISTRY BOOK& SG/SM, Chapter 5, Problem 39P , additional homework tip  3

Figure 2

There are three stereogenic centers present in ezetimibe.

Conclusion

There are three stereogenic centers present in ezetimibe.

Interpretation Introduction

(b)

Interpretation: Each stereogenic center in ezetimibe are to be labeled as R or S.

Concept introduction: A carbon atom that has four nonequivalent atoms or groups attached to it is known as chiral carbon atom. Chiral carbon centers are also called as asymmetric or stereogenic centers.

The naming of chiral center and geometric isomers are based on Cahn-Ingold-Prelog priority rules. If the priority assigned to each group attached to the chirality center in a molecule is in a clockwise direction, then it is the R-stereoisomer, and if this is counter-clockwise, then it is the S-stereoisomer. R and S-stereoisomer are mirror images of each other.

Expert Solution
Check Mark

Answer to Problem 39P

The R or S configuration of each stereogenic center in ezetimibe are shown below

ORGANIC CHEMISTRY BOOK& SG/SM, Chapter 5, Problem 39P , additional homework tip  4

Explanation of Solution

The R or S configuration of each stereogenic center in ezetimibe are shown below.

ORGANIC CHEMISTRY BOOK& SG/SM, Chapter 5, Problem 39P , additional homework tip  5

Figure 3

The stereogenic center (1) has S configuration because the rotation is clock-wise and least priority group is above the plane. The stereogenic center (2) has anti-clock wise rotation and least priority group is above the plane. Therefore, it has R configuration. The stereogenic center (3) has anti-clock wise rotation and least priority group is below the plane. Therefore, it has S configuration.

Conclusion

In ezetimibe, one of the stereogenic centers has R configuration and the other two possess S configuration.

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Determine the bond energy for HCI ( in kJ/mol HCI) using he balanced cremiculequecticnand bund energles listed? also c double bond to N is 615, read numbets carefully please!!!! Determine the bund energy for UCI (in kJ/mol cl) using me balanced chemical equation and bund energies listed? 51 (My (9) +312(g)-73(g) + 3(g) =-330. KJ спод bond energy Hryn H-H bond band 432 C-1 413 C=C 839 NH 391 C=O 1010 S-1 343 6-H 02 498 N-N 160 467 N=N C-C 341 CL- 243 418 339 N-Br 243 C-O 358 Br-Br C=C C-Br 274 193 614 (-1 216 (=olin (02) 799 C=N 618
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