Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
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Chapter 5, Problem D5.7P
To determine
The device width Wof the N channel MOSFET for the given parameters.
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Question 3 AC Motor Drives [15]Calculate the instantaneous currents delivered by the inverter if the direct axiscurrent required at a particular instant is 8.66A and the quadrature current is5A. Derive all equations for the three currents.
A certain signal f(t) has the following PSD (assume 12 load):
Sp (w) = new + 8(w) - 1.5) + (w + 1.5)]
(a) What is the mean power in the bandwidth w≤2 rad/see?
(b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec?
Paress(w) dw
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Chapter 5 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 5.1 - Prob. 5.1ECh. 5.1 - Prob. 5.2ECh. 5.1 - Prob. D5.3ECh. 5.2 - Prob. 5.4ECh. 5.2 - Prob. 5.5ECh. 5.2 - Prob. 5.6ECh. 5.2 - Prob. 5.7ECh. 5.3 - Prob. D5.8ECh. 5.3 - Prob. D5.9ECh. 5.3 - Prob. D5.10E
Ch. 5.3 - Prob. 5.11ECh. 5.3 - Prob. 5.12ECh. 5.3 - Prob. D5.13ECh. 5.3 - Prob. D5.14ECh. 5.3 - Prob. 5.15ECh. 5.4 - Prob. 5.16ECh. 5.4 - Prob. 5.17ECh. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. D5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. D5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10PCh. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. D5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. D5.32PCh. 5 - Prob. D5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. D5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. D5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. D5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. D5.48PCh. 5 - Prob. D5.49PCh. 5 - Prob. D5.50PCh. 5 - Prob. D5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. D5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67P
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- Can you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forward
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How a MOSFET Works - with animation! | Intermediate Electronics; Author: CircuitBread;https://www.youtube.com/watch?v=Bfvyj88Hs_o;License: Standard Youtube License