Explanation Given info: The temperature of the lead bullet is 100 °C , the specific heat of lead is 0.13 kJ/kg ⋅ °C , the heat of fusion of lead is 25 kJ/kg and the melting temperature of lead is 330 °C . Write the expression for the kinetic energy of a moving object. K E = 1 2 m v 2 (1) Here, K E is the kinetic energy m is the mass of the object v is the speed of the object Write the expression for the heat energy corresponding to the temperature change. Q 1 = m c Δ T (2) Here, Q 1 is the heat energy absorbed to change the temperature of the object c is the specific heat of the object Δ T is the change in temperature Write the expression for the heat energy corresponding to the change of state. Q 2 = m L (3) Here, Q 2 is the heat absorbed during change of state L is the latent heat Since the bullet after striking the steel plate melts, its temperature changes to the melting point and then it undergoes the change of state from solid to liquid. Thus, the total energy required for this process is obtained from the minimum kinetic energy of the bullet. K E = Q 1 + Q 2 (4) Use equation (1), (2) and (3) in (4). 1 2 m v 2 = m c Δ T + m L = m c ( T 2 − T 1 ) + m L Here, T 1 is the initial temperature of the bullet T 2 is the final temperature of the bullet Solve for v

16th Edition

ISBN: 9780077862619

Author: KRAUSKOPF, Konrad B. (konrad Bates), Beiser, Arthur

Publisher: Mcgraw-hill Education,

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Chapter 5, Problem 86E

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The minimum speed of the bullet.

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Chapter 5, Problem 85E

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The minimum speed of the bullet.

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