The diatomic gas having a density of 3.164 g/L at STP should be identified. Concept introduction: STP : standard temperature and pressure, it is the condition of 273.2 K and 1 atm . The molar volume of gases at STP condition is similar and it is close to the molar volume of an ideal gas at STP condition. That is, 22.42 L. Hence, at STP the molar volume of a gas is considered as 22.42L. Equation for density is, Density = Mass Volume According to ideal gas equation for molecular mass, Molecular mass = Mass * R * Temperature Volume * pressure
The diatomic gas having a density of 3.164 g/L at STP should be identified. Concept introduction: STP : standard temperature and pressure, it is the condition of 273.2 K and 1 atm . The molar volume of gases at STP condition is similar and it is close to the molar volume of an ideal gas at STP condition. That is, 22.42 L. Hence, at STP the molar volume of a gas is considered as 22.42L. Equation for density is, Density = Mass Volume According to ideal gas equation for molecular mass, Molecular mass = Mass * R * Temperature Volume * pressure
Solution Summary: The author explains that the diatomic gas having a density of 3.164 g/L at STP is Chlorine.
The diatomic gas having a density of 3.164 g/L at STP should be identified.
Concept introduction:
STP: standard temperature and pressure, it is the condition of
273.2K and 1 atm.
The molar volume of gases at STP condition is similar and it is close to the molar volume of an ideal gas at STP condition. That is, 22.42 L. Hence, at STP the molar volume of a gas is considered as 22.42L.
Equation for density is,
Density=MassVolume
According to ideal gas equation for molecular mass,
The rate constant for the decay of a radioactive element is 2.28 × 10⁻³ day⁻¹. What is the half-life of this element in days?
Handwritten please
Choose the best reagents to
complete the following
reaction.
i
H
A
B
1. CH3CH2Na
2. H3O+
1.
CH3CH2MgBr
2. H3O+
1. CH3MgBr
Q
C
2. H3O+
1. H3O+
D
2. CH3MgBr
00
OH
Q
E
CH³MgBr
Chapter 5 Solutions
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