Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 78P
(a)
To determine
The ration of force exerted by the airplane seat on the pilot to the weight of the pilot.
(b)
To determine
The cause of blood pooling described by an observer in inertial frame of reference.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Titania, the largest moon of the planet Uranus, has 18the radiusof the earth and 1/1700 the mass of the earth. (a) What is the accelerationdue to gravity at the surface of Titania? (b) What is the average densityof Titania? (This is less than the density of rock, which is one piece ofevidence that Titania is made primarily of ice.)
7. The effects of atmospheric drag cannot be deglected, in general, on the dynamics of
objects moving through the air. The drag force is found to be FD
where p is the density of air, A is the cross sectional area of the object, v is the object's
velocity, and Cp is the so called drag coefficient. For a baseball Cp is measured to be
- .5ρA Cp υ?,
.3.
(a) If the baseball is launched vertically with a speed of 90 miles per hour, how high
will it travel? How would the answer change ignoring air resistance?
(b) What is the speed of the baseball when it comes back down? How would the
answer change if there was no air resistance?
(c) How long does it take for the baseball to go up? Down? How would the anwers
change in the absence of air resistance?
At what altitude L (km) above such that the weight of an object reduced to one-third of its earth-surface value?
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A space station, in the form of a wheel 120 m in diameter, rotates to provide an artificial gravity of 3.00 m/s2 for persons who walk around on the inner wall of the outer rim. Find the rate of the wheels rotation in revolutions per minute that will produce this effect.arrow_forwardSuppose the mass of a fully loaded module in which astronauts take off from the Moon is 1.00104kg . The thrust of its engines is 3.00104N . (a) Calculate the module’s magnitude of acceleration in a vertical takeoff from the Moon. (b) Could it lift off from Earth? If not, why not? If it could, calculate the magnitude of its acceleration.arrow_forwardA service elevator takes a load of garbage, mass 10.0 kg, from a floor of a skyscraper under construction, down to ground level, accelerating downward at a rate of 1.2m/s2 . Find the magnitude of the force the garbage exerts on the floor of the service elevator?arrow_forward
- The terminal velocity of a human being is 200 km/hr, and it takes about 12 seconds to achieve this. This calculation considers for air friction of course. What would a person’s speed be if they free fell for 12 seconds instead (no air friction present)?arrow_forwardA pilot with a mass of 50 kg comes out of a vertical dive in a circular arc such that at the bottom of the arc her upward acceleration is 3.5g. (a) How does the magnitude of the force exerted by the airplane seat on the pilot at the bottom of the arc compare to her weight? (What is the ratio of magnitude of the force exerted by the seat to the magnitude of the pilot's weight?) (b) Use Newton's laws of motion to explain why the pilot might be subject to a blackout.This means that an above normal volume of blood "pools" in her lower limbs. How would an inertial reference frame observer describe the cause of the blood pooling? (Do this on paper. Your instructor may ask you to turn in this work.) eBookarrow_forwardA 50 kg box is pushed with a force of 200 N along a horizontal surface. If the coefficient of friction between the box and the surface is 0.3, calculate the acceleration of the box. (Note: The gravitational acceleration can be assumed to be 9.8 m/s² unless stated otherwise.)arrow_forward
- Because of Earth’s rotation about its axis, a point onthe equator has a centripetal acceleration of 0.034 0 m/s2,whereas a point at the poles has no centripetal acceleration.(a) Show that, at the equator, the gravitational force on anobject (the object’s true weight) must exceed the object’sapparent weight. (b) What are the apparent weights of a75.0-kg person at the equator and at the poles? (Assume Earthis a uniform sphere and take g = 9.800 m/s2.)arrow_forwardA mass of 50 kg in space is subjected to an external vertical force of 160 N. If the local gravity acceleration is g = 9.78 m/s2 and if frictional effects are neglected, determine the acceleration of the mass if the external vertical force is acting (a) upward. (round off answer to 2 decimal places)arrow_forwardAn airplane in flight is subject to an air resistanceforce proportional to the square of its speed v. But there is an additionalresistive force because the airplane has wings. Air flowing over thewings is pushed down and slightly forward, so from Newton’s third lawthe air exerts a force on the wings and airplane that is up and slightlybackward (Fig.). The upward force is the lift force that keeps theairplane aloft, and the backward force is called induced drag. At flyingspeeds, induced drag is inversely proportional to v2, so the total airresistance force can be expressed by Fair = av2 + b/v2, where a andb are positive constants that depend on the shape and size of the airplaneand the density of the air. For a Cessna 150, a small single-engineairplane, a = 0.30 N . s2/m2 and b = 3.5 * 105 N . m2/s2. In steadyflight, the engine must provide a forward force that exactly balances theair resistance force. (a) Calculate the speed 1in km>h2 at which this airplanewill have the maximum…arrow_forward
- The acceleration due to gravity on Earth differs slightly from place to place, depending on topography (e.g., whether you areon a hill or in a valley) and subsurface geology (whether there is dense rock like iron ore as opposed to light rock like saltbeneath you.) The precise acceleration due to gravity can be calculated from data taken in an introductory physicslaboratory course. An object, usually a metal ball for which air resistance is negligible, is dropped and the time it takes to falla known distance is measured. Very precise results can be produced with this method ifsufficient care is taken in measuring the distance fallen and the elapsed time.arrow_forwarda block of mass m is initially traveling upward along a ramp at speed v. The coefficient of kinetic friction between the block and the ramp is Mk. (a) Using Newton's second law, solve for the normal force on the block due to the ramp. (b) Using Newton's second law solve for the acceleration of the block.arrow_forwardA car weighs 1100kg and can accelerate from 0 to 60m/h in 7.1 seconds on a flat ground. what is the steepest grade your driveway can be if your house is located on a hill? Assume no friction forces, and approximate the driveway as a straight inclined plane.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY