Chapter 5, Problem 6E

Write a program that takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English. So, if the user types in 932, the program should display

n

Remember to display “zero” if the user types in just a 0. (Note: This exercise is a hard one!)

Program Plan Intro

Program Plan:

• Include the required files
• Define the main function
  • Declare the variable “num1”, “num2”, “rt_digit”, “val”.
  • Get the number from the user.
  • Check whether “num1” not equal to “0”.
    • Find the remainder using mod operator.
    • Divide the “number” by “10”.
    • Multiply “val” to “num” and add with the “rt_digit”.
    • Condition for while loop to check whether the “val” not equals to “10”.
      • Multiply the “val” with “10”.
    • Assign the “rt_digit” to “0”.
    • Do until the condition fails.
      • Find the remainder using mod operator.
      • Check whether the “rt_digit” equals to “1”.
        • Print the value “one”.
      • Check whether the “rt_digit” equals to “2”.
        • Print the value “two”.
      • Check whether the “rt_digit” equals to “3”.
        • Print the value “three”.
      • Check whether the “rt_digit” equals to “4”.
        • Print the value “four”.
      • Check whether the “rt_digit” equals to “5”.
        • Print the value “five”.
      • Check whether the “rt_digit” equals to “6”.
        • Print the value “six”.
      • Check whether the “rt_digit” equals to “7”.
        • Print the value “seven”.
      • Check whether the “rt_digit” equals to “8”.
        • Print the value “eight”.
      • Check whether the “rt_digit” equals to “9”.
        • Print the value “nine”.
      • While loop to check the condition whether the “num2” not equal to “0”.

Program Description Answer

Program to display the numbers to their equivalent words.

Explanation of Solution

Program:

//Include required header files

#include <stdio.h>

//Main function

int main()

{

//Declare the required variable

int num1 = 0, rt_digit = 0, num2 = 0, val = 1;

//Get the number from the user

printf("\nEnter a number: ");

scanf("%i", &num1);

//While loop to check the condition

while (num1 != 0)

{

//Find the remainder using mod operator

rt_digit = num1 % 10;

//Divide the "num1" by "10"

num1 = num1 / 10;

//Multiply "val" to "num" and add with the "rt_digit"

num2 = num2 * val + rt_digit;

//While loop to check the condition

while (val != 10)

{

//Multiply "val" with "10"

val = val * 10;

}

}

//Assign the "rt_digit" to "0"

rt_digit = 0;

//Do until the condition fails

do {

//Find the remainder using mod operator

rt_digit = num2 % 10;

//Check whether the "rt_digit" equals to "0"

if (rt_digit == 0)

{

//Print the value zero

printf("zero ");

}

//Check whether the "rt_digit" equals to "1"

else if (rt_digit == 1)

{

//Print the value one

printf("one ");

}

//Check whether the "rt_digit" equals to "2"

else if (rt_digit == 2)

{

//Print the value two

printf("two ");

}

//Check whether the "rt_digit" equals to "3"

else if (rt_digit == 3)

{

//Print the value three

printf("three ");

}

//Check whether the "rt_digit" equals to "4"

else if (rt_digit == 4)

{

//Print the value four

printf("four ");

}

//Check whether the "rt_digit" equals to "5"

else if (rt_digit == 5)

{

//Print the value five

printf("five ");

}

//Check whether the "rt_digit" equals to "6"

else if (rt_digit == 6)

{

//Print the value six

printf("six ");

}

//Check whether the "rt_digit" equals to "7"

else if (rt_digit == 7)

{

//Print the value seven

printf("seven ");

}

//Check whether the "rt_digit" equals to "8"

else if (rt_digit == 8)

{

//Print the value eight

printf("eight ");

}

//Check whether the "rt_digit" equals to "9"

else

//Print the value nine

printf("nine ");

//Divide the "num2" by "10"

num2 = num2 / 10;

//While loop to check the condition

} while (num2 != 0);

//Return the value 0

return 0;

}

Sample Output

Enter a number:  56

five six