Chapter 5, Problem 62SE

Cervical Cancer About 8 women in 100,000 have cervical cancer $\left(\text{C}\right)$, so $\text{P}\left(\text{C}\right)=0.00008$ and P(no C) $=0.99992$. The chance that a Pap smear will incorrectly indicate that a woman without cervical cancer has cervical cancer is 0.03. Therefore,

P(test pos $|$ no C) $=0.03$

What is the probability that a randomly chosen women who has this test will both be free of cervical cancer and test positive for cervical cancer (a false positive)?