Explanation The required reaction is given below. C l 2 ( g ) + F 2 ( g ) ⇌ 2 C l F ( g ) , K = 20 The expression for equilibrium constant for the above reaction can be written as shown below, K = ( P C l F ) 2 ( P F 2 ) ( P C l 2 ) Given that, the initial partial pressures of C l 2 , F 2 , a n d C l F is 0.200 b a r , 0.100 b a r , a n d 0.100 b a r respectively. An equilibrium table can be set up as given below. C o m p o s i t i o n ( m b a r ) C l 2 F 2 C l F I n i t i a l p r e s s u r e 0.200 0.100 0.100 C h a n g e i n p r e s s u r e − x − x + 2 x E q u i l i b r i u m p r e s s u r e 0.200 − x 0.100 − x 0

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

7th Edition

ISBN: 9781319403959

Author: ATKINS

Publisher: MAC HIGHER

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Chapter 5, Problem 5I.4BST

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Interpretation:

The equilibrium partial pressure of ClF in the reaction mixture has to be calculated. The reaction is given below.

Cl2(g)+F2(g)⇌2ClF(g), K=20

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Chapter 5, Problem 5I.4AST

Chapter 5, Problem 5I.1E

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Chapter 5 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

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The equilibrium partial pressure of C l F in the reaction mixture has to be calculated. The reaction is given below. C l 2 ( g ) + F 2 ( g ) ⇌ 2 C l F ( g ) , K = 20

Solution Summary: The author explains how the equilibrium partial pressure of ClF in the reaction mixture has to be calculated.

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Interpretation:

The equilibrium partial pressure of ClF in the reaction mixture has to be calculated. The reaction is given below.

Cl2(g)+F2(g)⇌2ClF(g), K=20

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Chapter 5 Solutions

The equilibrium partial pressure of C l F in the reaction mixture has to be calculated. The reaction is given below. C l 2 ( g ) + F 2 ( g ) ⇌ 2 C l F ( g ) , K = 20

Solution Summary: The author explains how the equilibrium partial pressure of ClF in the reaction mixture has to be calculated.

Concept explainers

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Interpretation: The equilibrium partial pressure of ClF in the reaction mixture has to be calculated. The reaction is given below. Cl2(g)+F2(g)⇌2ClF(g), K=20

Want to see the full answer?

Chapter 5 Solutions

Interpretation:

The equilibrium partial pressure of ClF in the reaction mixture has to be calculated. The reaction is given below.

Cl2(g)+F2(g)⇌2ClF(g), K=20