Explanation The required reaction is given below. C O ( g ) + 3 H 2 ( g ) ⇌ C H 4 ( g ) + H 2 O ( g ) The expression for equilibrium constant for the above reaction can be written as shown below, K c = [ C H 4 ] [ H 2 O ] [ C O ] [ H 2 ] 3 Given that, 2.00 m o l C O a n d 3.00 m o l H 2 are placed in a reaction vessel of volume 10.00 L . Their concentrations can be calculated as given below. [ C O ] = m o l e s v o l u m e = 2 m o l 10.00 L = 0 . 2 M [ H 2 ] = m o l e s v o l u m e = 3 m o l 10.00 L = 0 . 3 M An equilibrium table can be set up as given below. C o m p o s i t i o n ( M ) C O H 2 C H 4 H 2 O I n i t i a l c o n c e n t r a t i o n 0.2 0.3 0 0 C h a n g e i n c o n c e n t r a t i o n − x − 3 x + x + x E q u i l i b r i u m c o n c e n t r a t i o n 0

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

7th Edition

ISBN: 9781319403959

Author: ATKINS

Publisher: MAC HIGHER

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Chapter 5, Problem 5I.23E

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Interpretation:

The value of Kc for the reaction CO(g)+3H2(g)⇌CH4(g)+H2O(g) has to be calculated.

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Chapter 5, Problem 5I.22E

Chapter 5, Problem 5I.24E

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Chapter 5 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

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The value of K c for the reaction C O ( g ) + 3 H 2 ( g ) ⇌ C H 4 ( g ) + H 2 O ( g ) has to be calculated.

Solution Summary: The author explains that the value of K_c for the reaction is given below.

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Interpretation:

The value of Kc for the reaction CO(g)+3H2(g)⇌CH4(g)+H2O(g) has to be calculated.

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Chapter 5 Solutions

The value of K c for the reaction C O ( g ) + 3 H 2 ( g ) ⇌ C H 4 ( g ) + H 2 O ( g ) has to be calculated.

Solution Summary: The author explains that the value of K_c for the reaction is given below.

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Interpretation: The value of Kc for the reaction CO(g)+3H2(g)⇌CH4(g)+H2O(g) has to be calculated.

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Chapter 5 Solutions

Interpretation:

The value of Kc for the reaction CO(g)+3H2(g)⇌CH4(g)+H2O(g) has to be calculated.