The amount of NO passing through the hole is needed to be determined. Concept introduction: Rate at which the effusion of gas occur can be calculated by dividing moles of gas (n) to time of effusion (t). Therefore, formula of rate of effusion is - r a t e = ( n t ) Rate of effusion is also inversely proportional to the square root of the molar mass of gas.Therefore, the ratio of rate of effusion of gases is given by following formula- R a t e o f e f f u s i o n o f g a s A R a t e o f e f f u s i o n o f g a s B = ( M o l a r m a s s o f g a s B M o l a r m a s s o f g a s A ) 1 / 2

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1/2 - 51% + » GAY Organic Reactions Assignment /26 Write the type of reaction that is occurring on the line provided then complete the reaction. Only include the major products and any byproducts (e.g. H₂O) but no minor products. Please use either full structural diagrams or the combination method shown in the lesson. Skeletal/line diagrams will not be accepted. H3C 1. 2. CH3 A Acid OH Type of Reaction: NH Type of Reaction: + H₂O Catalyst + HBr 3. Type of Reaction: H3C 4. Type Reaction: 5. H3C CH2 + H2O OH + [0] CH3 Type of Reaction: 6. OH CH3 HO CH3 + Type of Reaction: 7. Type of Reaction: + [H]

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Question

Chapter 5, Problem 59QAP

Interpretation Introduction

Interpretation:

The amount of NO passing through the hole is needed to be determined.

Concept introduction:

Rate at which the effusion of gas occur can be calculated by dividing moles of gas (n) to time of effusion (t). Therefore, formula of rate of effusion is -

rate=(nt)

Rate of effusion is also inversely proportional to the square root of the molar mass of gas.Therefore, the ratio of rate of effusion of gases is given by following formula-

Rate of effusion of gas ARate of effusion of gas B=(Molar mass of gas BMolar mass of gas A)1/2

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