Chapter 5, Problem 5.7P

Interpretation Introduction

(a)

Interpretation:

The volume of water in the tank before addition of the crystals needs to be determined.

Concept introduction:

The height of the tank $\left(h\right)$ is defined as the ratio of volume of liquid $\left(V\right)$ to the area of the given tank $\left(A\right)$

$h=\frac{V}{A}$

Interpretation Introduction

(b)

Interpretation:

The height of liquid in the tank before the addition of crystals needs to be calculated, if the tank diameter is $\text{0}\text{.30 m}$.

Concept introduction:

The height of the tank $\left(h\right)$ is defined as the ratio of volume of liquid $\left(V\right)$ to the area of the given tank $\left(A\right)$

$h=\frac{V}{A}$

Interpretation Introduction

(c)

Interpretation:

The height of the water in the tank after addition of the crystals but before they get dissolved needs to be determined.

Concept introduction:

The volume of anhydrous liquid after crystals added $\left({V^{\prime }}_a\right)$ is calculated from,

${V^{\prime }}_a=\frac{m_a}{{\rho }_a}$

Height of anhydrous liquid $\left({h^{\prime }}_a\right)$ is calculated as

${h^{\prime }}_a=\frac{{V^{\prime }}_a+V_a}{A}$

Interpretation Introduction

(d)

Interpretation:

The height of liquid in the tank after all the ${\text{MgSO}}_{\text{4}}$ is dissolved needs to be determined.

Concept introduction:

The volume of liquid after ${\text{MgSO}}_{\text{4}}$ has dissolved $\left(V\right)$ is calculated as

$V=\frac{m}{\rho }$

The height of the tank $\left(h\right)$ is defined as the ratio of Volume of liquid $\left(V\right)$ to the Area of the given tank $\left(A\right)$

$h=\frac{V}{A}$