EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
4th Edition
ISBN: 9781119192107
Author: BULLARD
Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT
Question
Book Icon
Chapter 2, Problem 2.1P
Interpretation Introduction

(a)

Interpretation:

: To convert 2 wk to microseconds.

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol. d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In two weeks there are 1.2×1012μs.

Explanation of Solution

In one week there are seven days and in one day there are twenty-four hours. In one hour there are sixty minutes and in one minute there are sixty seconds. In one second there are 106 microseconds.

Convert week to microseconds as follows:

2wk=(2wk)(7d1wk)(24h1d)(60min1h)(60s1min)(106μs1s)=1.2×1012μs.

Interpretation Introduction

(b)

Interpretation:

To convert 38.1 ft/s to kilometers/h.

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In 38.1 fts there are 41.8 kmh.

Explanation of Solution

In one day there are twenty-four hours and in one hour there are sixty minutes.

In one pound there are 0.453593 kg and in one feet there are 0.3048 m. Convert meter per day into kilogram to feet per minute into pound as follows:

554m4daykg=(554m4daykg)(1day24 h)(1h60min)(0.453593kg1lbm)(1ft4(0.3048 m)4)=20.2ft4minlbm.

Interpretation Introduction

(c)

Interpretation:

To convert 554 m4/(day.kg) to ft4/(min.lbm ).

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In 554m4daykg there are 20.2ft4minlbm.

Explanation of Solution

In one day there are twenty-four hours and in one hour there are sixty minutes.

In one pound there are 0.453593 kg and in one feet there are 0.3048 m. Convert meter per day into kilogram to feet per minute into pound as follows:

554m4daykg=(554m4daykg)(1day24 h)(1h60min)(0.453593kg1lbm)(1ft4(0.3048m)4)=20.2ft4minlbm.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
01:49
Students have asked these similar questions
Predict the organic products that form in the reaction below: + OH +H H+ ➤ ☑ X - Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. G
Predict the organic products that form in the reaction below: OH H+ H+ + ☑ Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. ✓ m
Determine the structures of the missing organic molecules in the following reaction: + H₂O +H H+ Y Z ☑ ☑ Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structures of the missing organic molecules X, Y, and Z. You may draw the structures in any arrangement that you like, so long as they aren't touching. Molecule X shows up in multiple steps, but you only have to draw its structure once. Click and drag to start drawing a structure. AP +
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Text book image
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:9781285640686
Author:Skoog
Publisher:Cengage