(a)
Interpretation:
The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.
Concept introduction:
The straight-line plot has following equation:
Here, 
values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and 
is intercept.
And, the following equation shows the exponential plot:
(b)
Interpretation:
The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.
Concept introduction:
The straight-line plot has following equation:
Here, 
values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and 
is intercept.
And, the following equation shows the exponential plot:
(c)
Interpretation:
A log pot y versus x passes through (1,2) and (2,1), determine the equation.
Concept introduction:
The straight-line plot has following equation:
Here, 
values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and 
is intercept.
And, the following equation shows the exponential plot:
(d)
Interpretation:
A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.
Concept introduction:
The straight-line plot has following equation:
Here, 
values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and 
is intercept.
And, the following equation shows the exponential plot:
(e)
Interpretation:
The equation of log plot of y2/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)
Concept introduction:
The straight-line plot has following equation:
Here, 
values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and 
is intercept.
And, the following equation shows the exponential plot:
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Chapter 2 Solutions
EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
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