(a) Interpretation: The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn. Concept introduction: The straight-line plot has following equation: Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept. And, the following equation shows the exponential plot:

Question

Chemistry In an analysis of the content of carbohydrate present in a glycoprotein, the following results were found: 12.6, 11.9, 13.0, 12.7 and 12.5 g of carbohydrate per 100 g of protein. Taking into account that σ is unknown, the confidence interval for the average value at a 90% confidence level of the carbohydrate content is: Select one:to. 12.5 ± 0.4b. 12.5 ± 0.2c. 12.5 ± 0.5d. 12.5 ± 0.3

Answer 1

Question

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

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Chemistry In an analysis of the content of carbohydrate present in a glycoprotein, the following results were found: 12.6, 11.9, 13.0, 12.7 and 12.5 g of carbohydrate per 100 g of protein. Taking into account that σ is unknown, the confidence interval for the average value at a 90% confidence level of the carbohydrate content is: Select one:to. 12.5 ± 0.4b. 12.5 ± 0.2c. 12.5 ± 0.5d. 12.5 ± 0.3

Normal text Times New. - 12 BIUA + E- 1E = E - E - EEX ... .. 2 3 1 4 I I. c. Water from the sodium hydroxide solution 15 I . 16 ... I7 .. 6. Students collected the following temperature data for a coffee cup calorimetry experiment: Table 1. Temperature of solution with time for the reaction of baking soda with vinegar as measured in a coffee cup calorimeter. Time since start of reaction Temperatu re (°C) nent will (min) 24.6 0.5 20.9 1.1 20.1 1.4 19.3 1.7 18.5 2.1 18.4 2.5 18.3 2.9 18.2 3.5 18.4 a. Calculate AT and show your work. b. Is the reaction endothermic or exothermic? MacBook Air DII F6 80 F4 F3 &. $ 23 5 4 2 3 Y W K H G F S M V CO

2. Set the two equations equal and isolate In Ksp on one side of the equals sign by dividing both sides by (-RT). AG=RT'In Ksp=AH-TAS/-RT AG=In KSR=AH-TAS/-RT| 3. Create a graph using Excel plotting In Ksp on the y-axis and 1/T (make sure the units for temperature are Kelvin) on the x-axis. I In KSP 0 0.0029 -0.5 -1 -1.5 -2 -2.5 -3 -3.5 -4 -4.5 -5 0.003 0.0031 0.0032 1/T 0.0033 0.0034 0.0035 y=-2738x+5.075 R² = 0.9845 0.0036 a. Use the value obtained for the slope of the graph to solve for AH° using the equation derived in Question 2.

Answer 2

Question

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

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Answer 3

Question

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

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Answer 4

Question

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

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Answer 5

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 6

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 7

Chapter 2, Problem 2.38P

Interpretation Introduction

(a)

Interpretation:

The plot of ln y versus x on rectangular coordinates passes through (1.0, 693) and (2,0) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 8

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 9

Interpretation Introduction

(b)

Interpretation:

The semilog plot of y versus x passes through (1,2) and (2,1) should be drawn.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 10

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 11

Interpretation Introduction

(c)

Interpretation:

A log pot y versus x passes through (1,2) and (2,1), determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 12

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 13

Interpretation Introduction

(d)

Interpretation:

A semilog plot of xy (logarithmic axis) versus y/x passes through (1.0. 40.2). Determine the equation.

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 14

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 15

Interpretation Introduction

(e)

Interpretation:

The equation of log plot of y²/x versus (x-2) passes through (1.0, 40.2) and (2.0, 807.0)

Concept introduction:

The straight-line plot has following equation:

Here, values are plotted at y axis, x values are plotted at x axis, b is slope of the reaction and is intercept.

And, the following equation shows the exponential plot:

Answer 16

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Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P

Chapter 2 Solutions