(a) Interpretation: Fit a line to given data using the method of least squares. Concept introduction: The method of least square for a y = ax + b line is given as, here, a and b can be calculated as, S x y = 1 n ∑ i = 1 n X i Y i S x x = 1 n ∑ i = 1 n X i 2 S x = 1 n ∑ i = 1 n X i h e n c e , a = S x y − S x S y S x x − ( S x ) 2 b = S x x S y − S x S x y S x x − ( S x ) 2

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Answer 1

Question

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

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5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.

None

Stereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)

Answer 2

Question

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Answer 6

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Answer 7

Chapter 2, Problem 2.48P

Interpretation Introduction

(a)

Interpretation:

Fit a line to given data using the method of least squares.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Answer 8

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Answer 9

Interpretation Introduction

(b)

Interpretation:

Fit a line through the origin using the same data set.

Concept introduction:

The method of least square for a y = ax + b line is given as, here, a and b can be calculated as,

Sxy = 1n ∑i=1nXiYiSxx =1n∑i=1nXi2Sx = 1n∑i=1nXi

hence,a = Sxy−Sx Sy Sxx − (Sx )2b = SxxSy−Sx Sxy Sxx − (Sx )2

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P

Solution Summary: The author explains how the method of least squares is used to fit a line to given data.

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Chapter 2 Solutions