Interpretation Introduction To determine: The energies in kilojoules per mole Explanation Given: Infrared radiation with wave length λ=1 .55×10 -6 m Ultra violet radiation with wave length λ=250 nm X-ray radiation with wave length 5 .49 nm Wave length ( λ ): Wave length is a distance between two consecutive crests or troughs of a wave. Frequency ( ν ): Frequency is the number of consecutive crests or thoughts (wave cycle) of that pass a given point in unit time. ν = c λ Formula used: E=hν E=h c λ where, E=energy, h = Plank's constant (6 .626 ×10 -34 J×s) ν = frequency, λ = Wave length c = speed of light (2 .998 × 10 8 m/s) Calculation: Energy for one photon: E = hc λ E= 6 .626 ×10 -34 J× s ×2 .998 × 10 8 m / s 1 .55×10 -6 m E=1 .28×10 -19 J The energy in kilojoules per mole: The energy in joule per photon = 1.28 × 10 − 19 J 1 mol photon = 6.022 × 10 23 photons 1 kJ = 1000 J To calculate the energy in kilojoules per mole we use the following solution: E= 1 .28×10 -19 J 1 photon × 6 .022×10 23 photons 1 m o l p h o t o n × 1kJ 1000 J E=77 .1 k J m o l Convert wavelength in meters: 1 nm = 1×10 -9 m 250 nm × 1×10 -9 m 1 .00 nm =2 .50×10 -7 m Energy for one photon: E = hc λ E= 6 .626 ×10 -34 J× s ×2 .998 × 10 8 m / s 2

Chemistry, Books a la Carte Plus Mastering Chemistry with eText -- Access Card Package (7th Edition)

7th Edition

ISBN: 9780133900811

Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson

Publisher: PEARSON

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Chapter 5, Problem 5.3P

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The energies in kilojoules per mole

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Chemistry, Books a la Carte Plus Mastering Chemistry with eText -- Access Card Package (7th Edition)

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