Chapter 5, Problem 5.36QP

Interpretation Introduction

Interpretation:

The final pressure of the gas in atmospheres has to be calculated.

Concept Introduction:

STP in chemistry is the short form for Standard Temperature and Pressure.  STP is mostly used when performing calculations on gases, such as gas density.

Use the combined gas law

$\frac{{\text{P}}_{\text{1}}{\text{V}}_{\text{1}}}{{\text{T}}_{\text{1}}}\text{=}\frac{{\text{P}}_{\text{2}}{\text{V}}_{\text{2}}}{{\text{T}}_{\text{2}}}$

$\begin{array}{l}\text{where,}{\text{P}}_{\text{1}}\text{,}{\text{V}}_{\text{1}}\text{,}{\text{n}}_{\text{1}}\text{,}\text{and}{\text{T}}_{\text{1}}\text{are}\text{the}\text{initial}\text{}\text{pressure,}\text{volume,and}\\ \text{temperature}\text{.}\text{And}{\text{P}}_{\text{2}}{\text{,V}}_{\text{2}}\text{and}{\text{T}}_{\text{2}}\text{are}\text{the}\text{final}\text{pressure,}\text{volume,}\text{and}\text{temperature}\text{.}\\ \text{volume}\text{remains}\text{same}\\ \text{so}\\ {\text{V}}_{\text{1}}{\text{=V}}_{\text{2}}\text{=V}\\ \text{from}\text{the}\text{above}\text{equation}\text{we}\text{can}\text{write}\\ \frac{{\text{P}}_{\text{1}}}{{\text{T}}_{\text{1}}}\text{= }\frac{{\text{P}}_{\text{2}}}{{\text{T}}_{\text{2}}}\end{array}$