(a) Interpretation: The missing reactant or product for the given equation is to be stated. Concept introduction: In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH 3 SCH 3 .

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Answer 1

Question

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

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Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions ΔΗ is (pick one) A This reaction is faster above 103. °C than below. AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous only above -9. °C. AS is (pick one) ΔΗ is (pick one) C The reverse of this reaction is always spontaneous. AS is (pick one) 18 Ar

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Answer 2

Question

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

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Answer 3

Question

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

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Answer 4

Question

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

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Answer 5

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

Answer 6

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Answer 7

Chapter 5, Problem 5.31AP

Interpretation Introduction

(a)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

In the presence of ozone and CH3SCH3, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of CH3SCH3.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Answer 12

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Answer 13

Interpretation Introduction

(d)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

The reaction of hydrogen halide with alkene results in the formation of alkyl halide. This type of reaction is an electrophilic addition of hydrogen halide. Electrophilic addition reactions are those in which breaking of pi bond take place to form new sigma bond.

Answer 14

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

Answer 15

Interpretation Introduction

(e)

Interpretation:

The missing reactant or product for the given equation is to be stated.

Concept introduction:

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-Markovnikov rule.

Anti markovinkov rule states that the positive part of acid attached to that carbon atom in C=C bond which carries minimum number of hydrogen atoms and the negative part of acid will attach to that carbon atom in C=C bond which has maximum number of hydrogen atoms.

Answer 16

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Answer 17

Expert Solution & Answer

Answer 18

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Answer 19

Ch. 5 - Prob. 5.1P Ch. 5 - Prob. 5.2P Ch. 5 - Prob. 5.3P Ch. 5 - Prob. 5.4P Ch. 5 - Prob. 5.5P Ch. 5 - Prob. 5.6P Ch. 5 - Prob. 5.7P Ch. 5 - Prob. 5.8P Ch. 5 - Prob. 5.9P Ch. 5 - Prob. 5.10P

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