Chapter 5, Problem 5.27AP

Interpretation Introduction

(a)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{Br}}_{\text{2}}$ in ${\text{CH}}_{\text{2}}{\text{Cl}}_{\text{2}}$ solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and ${\text{Br}}_{\text{2}}$ in ${\text{CH}}_{\text{2}}{\text{Cl}}_{\text{2}}$ solvent is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ and ${\text{Br}}_{\text{2}}$ in ${\text{CH}}_{\text{2}}{\text{Cl}}_{\text{2}}$ undergoes electrophilic substitution reaction. It results in the formation of $1,2-\text{dibromobutane}$ a substitution product. The complete reaction is shown below.

Figure 1

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and ${\text{Br}}_{\text{2}}$ in ${\text{CH}}_{\text{2}}{\text{Cl}}_{\text{2}}$ solvent is shown in Figure 1.

Interpretation Introduction

(b)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{O}}_{\text{3}}$ at $78°\text{C}$ is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and ${\text{O}}_{\text{3}}$ at $78°\text{C}$ is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with a molecule of ozone at $-78°\text{C}$ temperature undergoes ozonolysis reaction. It results in the formation of ozonolysis adduct. The complete reaction is shown below.

Figure 2

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and ${\text{O}}_{\text{3}}$ at $78°\text{C}$ is shown in Figure 2.

Interpretation Introduction

(c)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{S}$ solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of the product of (b) with ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{S}$ solvent is shown below.

Explanation of Solution

The reaction of the product (b) that is ozonolysis adduct with ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{S}$ solvent undergoes reduction reaction. It results in the formation of propionaldehyde or propanaldehyde and formaldehyde. The complete reaction is shown below.

Figure 3

Conclusion

The products obtained from the reaction of the product of (b) with ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{S}$ solvent is shown in Figure 3.

Interpretation Introduction

(d)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solventis to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of the product of (b) with ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent is shown below.

Explanation of Solution

The reaction of the product of part (b) with ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent undergoes oxidation reaction. It results in the formation of propanoic acid and formic acid. The complete reaction is shown below.

Figure 4

Conclusion

The products obtained from the reaction of the product of (b) with ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent is shown in Figure 4.

Interpretation Introduction

(e)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{O}}_{\text{2}}$, flame is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and ${\text{O}}_{\text{2}}$, flame is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with oxygen in the presence of flame undergoes combustion reaction. it results in the formation of four molecules of carbon dioxide and three molecules of water. The complete reaction is shown below.

Figure 5

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and ${\text{O}}_{\text{2}}$, flame is shown in Figure 5.

Interpretation Introduction

(f)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and $\text{HBr}$ solventis to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and $\text{HBr}$ solvent is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with $\text{HBr}$ reagent. It results in the formation of $2-\text{bromobutane}$. The addition of $\text{HBr}$ reagent follows Markovinkov rule that is a negative part of reagent attached to that carbon which has a lesser number of the hydrogen atom. The reaction is shown below.

Figure 6

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and $\text{HBr}$ solvent is shown in Figure 6.

Interpretation Introduction

(g)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{I}}_{\text{2}}\text{,}{\text{H}}_{\text{2}}\text{O}$ solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and ${\text{I}}_{\text{2}}\text{,}{\text{H}}_{\text{2}}\text{O}$ solvent is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with ${\text{I}}_{\text{2}}\text{,}{\text{H}}_{\text{2}}\text{O}$ reagent. It results in the formation of $1-\text{iodobutan-2-ol}$. The addition of ${\text{I}}_{\text{2}}\text{,}{\text{H}}_{\text{2}}\text{O}$ reagent follows Markovinkov rule that is a negative part of reagent attached to that carbon which has a lesser number of the hydrogen atom. The reaction is shown below.

Figure 7

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and ${\text{I}}_{\text{2}}\text{,}{\text{H}}_{\text{2}}\text{O}$ solvent is shown in Figure 7.

Interpretation Introduction

(h)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{H}}_{\text{2}}\text{,}\text{Pt}/\text{C}$ is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and ${\text{H}}_{\text{2}}\text{,}\text{Pt}/\text{C}$ is shown below.

Explanation of Solution

The reaction $1-\text{butene}$ with ${\text{H}}_{\text{2}}\text{,}\text{Pt}/\text{C}$ undergoes hydrogenation reaction. It results in the formation of butane compound. The complete reaction is shown below.

Figure 8

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and ${\text{H}}_{\text{2}}\text{,}\text{Pt}/\text{C}$ is shown in Figure 8.

Interpretation Introduction

(i)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and $\text{HBr}$ in peroxide solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and $\text{HBr}$ in peroxide solvent is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with $\text{HBr}$ in peroxide reagent. It results in the formation of $1-\text{bromobutane}$. The addition of $\text{HBr}$ reagent in peroxide follows Anti-Markovinkov rule that is a negative part of reagent attached to that carbon which has a greater number of the hydrogen atom. The reaction is shown below.

Figure 9

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and $\text{HBr}$ in peroxide solvent is shown in Figure 9.

Interpretation Introduction

(j)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and ${\text{BH}}_3$ in THF solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and ${\text{BH}}_3$ in THF solvent is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with ${\text{BH}}_3$ in THF solvent undergoes hydroboration reaction with three molecules of borane. It results in the formation of trialkyl borane adduct. The reaction is shown below.

Figure 10

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and ${\text{BH}}_3$ in THF solvent is shown in Figure 10.

Interpretation Introduction

(k)

Interpretation:

The products obtained from the reaction of the product of part (j) and $\text{NaOH,}{\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of the product of part (j) and $\text{NaOH,}{\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent is shown below.

Explanation of Solution

The reaction of a trialkyl borane adduct that is obtained from part (j) with $\text{NaOH,}{\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent undergoes oxidation reaction. It results in the formation of $\text{butan-2-ol}$. The oxidation reaction follows Markovinkov rule that is a negative part of reagent attached to that carbon which has a lesser number of the hydrogen atom. The reaction is shown below.

Figure 11

Conclusion

The products obtained from the reaction of the product of part (j) and $\text{NaOH,}{\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ solvent is shown in Figure 11.

Interpretation Introduction

(l)

Interpretation:

The products obtained from the reaction of $1-\text{butene}$ and $\text{Hg}{\left(\text{OAc}\right)}_2$ in ${\text{H}}_{\text{2}}\text{O}$ solvent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $1-\text{butene}$ and $\text{Hg}{\left(\text{OAc}\right)}_2$ in ${\text{H}}_{\text{2}}\text{O}$ solvent is shown below.

Explanation of Solution

The reaction of $1-\text{butene}$ with $\text{Hg}{\left(\text{OAc}\right)}_2$ in ${\text{H}}_{\text{2}}\text{O}$ solvent undergoes oxymercuration reaction. This reaction follows Markovinkov rule that is a negative part of reagent attached to that carbon which has a lesser number of the hydrogen atom. It results in the formation of the oxymercuration adduct product. The reaction is shown below.

Figure 12

Conclusion

The products obtained from the reaction of $1-\text{butene}$ and $\text{Hg}{\left(\text{OAc}\right)}_2$ in ${\text{H}}_{\text{2}}\text{O}$ solvent is shown in Figure 12.

Interpretation Introduction

(m)

Interpretation:

The products obtained from the reaction of the product of part (l) and ${\text{NaBH}}_{\text{4}}\text{/NaOH}$ solventis to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration.

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of the product of part (l) and ${\text{NaBH}}_{\text{4}}\text{/NaOH}$ solvent is shown below.

Explanation of Solution

The reaction of the product of part (l) reaction with ${\text{NaBH}}_{\text{4}}\text{/NaOH}$ solvent undergoes oxidation reaction. This oxidation reaction follows Markovinkov rule that is a negative part of reagent attached to that carbon which has a lesser number of the hydrogen atom. It results in the formation of $\text{2-butanol}$. The reaction is shown below.

Figure 13

Conclusion

The products obtained from the reaction of the product of part (l) and ${\text{NaBH}}_{\text{4}}\text{/NaOH}$ solvent is shown in Figure 13.

Interpretation Introduction

(n)

Interpretation:

The products obtained from the reaction of $\text{1-butene}$ and the given reagent is to be stated.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration. The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $\text{1-butene}$ and $\text{HI}$ solvent is shown below.

Explanation of Solution

The reaction of $\text{1-butene}$ and $\text{HI}$ solvent undergoes addition reaction. This reaction follows Markovinkov rule that is a negative part of reagent attached to that carbon which has a lesser number of the hydrogen atom. It results in the formation of $\text{2-iodobutane}$. The reaction is shown below.

Figure 14

Conclusion

The products obtained from the reaction of $\text{1-butene}$ and $\text{HI}$ solvent is to be stated.

Interpretation Introduction

(o)

Interpretation:

The products obtained from the reaction of $\text{1-butene}$ and $\text{HI, AIBN}$ solvent is shown in Figure 14.

Concept introduction:

Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as ${\text{C}}_{\text{n}}{\text{H}}_{\text{2n}}$. They give rise to geometrical and stereoisomers- $cis-trans$ or $E-Z$ configuration. The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.

Answer to Problem 5.27AP

The products obtained from the reaction of $\text{1-butene}$ and $\text{HI, AIBN}$ solvent is shown below.

Explanation of Solution

The reaction of $\text{1-butene}$ with $\text{HI, AIBN}$ Solvent undergoes radical addition reaction. It results in the formation of iodobutane addition product. The reaction follows Anti-Markovinkov rule that is a negative part of reagent attached to that carbon which has a greater number of the hydrogen atom. The reaction is shown below.

Figure 15

Conclusion

The products obtained from the reaction of $\text{1-butene}$ and $\text{HI, AIBN}$ solvent is shown in Figure 15.