
Concept explainers
(a)
Interpretation:
The electrophilic group for the given reaction is to be identified.
Concept introduction:
The replacement or substitution of one

Answer to Problem 5.1P
In the given reaction, iodine cation is behaving as an electrophile.
Explanation of Solution
In acid catalyzed hydration reaction, nucleophile goes to the more substituted carbon of the
In the given reaction, addition of electrophile over carbon-carbon double bond takes place. This will result in the formation of intermediate that is carbocation. Thus, the addition of electrophile is at less substituted carbon of the alkene to give the desired product as shown below.
Figure 1
In this case, azide ion is behaving as a nucleophile, whereas iodine cation is behaving as an electrophile.
In the given reaction, iodine cation is behaving as an electrophile.
(b)
Interpretation:
The product formed by the given reaction is to be stated.
Concept introduction:
The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron rich chemical species that contains negative charge or lone pair of electrons are known as a nucleophile. In a nucleophilic substitution reaction, nucleophile takes the position of leaving group by attacking the electron deficient carbon atom.

Answer to Problem 5.1P
The product formed by the given reaction is shown below.
Explanation of Solution
The given reaction is,
Figure 2
The electronegativity of bromine is higher than iodine, thus due to which in iodine bromide iodine will act as an electrophile, whereas bromide ion will act as a nucleophile. The given reaction will follow Markovnikov’s rule to form the desired product as shown below.
Figure 3
The product formed by the given reaction is shown in Figure 3.
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Chapter 5 Solutions
Organic Chemistry, Ebook And Single-course Homework Access
- 2. Name the following hydrocarbons. (9 marks) a) HHHHHHHH H-C-C- H-O-S b) HCEC-CH3 H H H H H d) c) H C=C- H H H e) CH3 CH3 CH2CH=CH-CH=CHCH3 HHHH H-C-C-C-C-H H HH H f) large CH2CH3 pola H3C section lovels tower, able ocart firs g) Tower H3C-CH2 then in H3C-CH-CH-CH3 enblbano bne noitsidab Copyright © 2008. Durham Continuing Education CH3arrow_forwardName the molecules & Identify any chiral center CH3CH2CH2CHCH₂CH₂CH₂CH₂ OH CH₂CHCH2CH3 Br CH3 CH3CHCH2CHCH2CH3 CH3arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
