
Concept explainers
(a)
Interpretation:
The electrophilic group for the given reaction is to be identified.
Concept introduction:
The replacement or substitution of one

Answer to Problem 5.1P
In the given reaction, iodine cation is behaving as an electrophile.
Explanation of Solution
In acid catalyzed hydration reaction, nucleophile goes to the more substituted carbon of the
In the given reaction, addition of electrophile over carbon-carbon double bond takes place. This will result in the formation of intermediate that is carbocation. Thus, the addition of electrophile is at less substituted carbon of the alkene to give the desired product as shown below.
Figure 1
In this case, azide ion is behaving as a nucleophile, whereas iodine cation is behaving as an electrophile.
In the given reaction, iodine cation is behaving as an electrophile.
(b)
Interpretation:
The product formed by the given reaction is to be stated.
Concept introduction:
The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron rich chemical species that contains negative charge or lone pair of electrons are known as a nucleophile. In a nucleophilic substitution reaction, nucleophile takes the position of leaving group by attacking the electron deficient carbon atom.

Answer to Problem 5.1P
The product formed by the given reaction is shown below.
Explanation of Solution
The given reaction is,
Figure 2
The electronegativity of bromine is higher than iodine, thus due to which in iodine bromide iodine will act as an electrophile, whereas bromide ion will act as a nucleophile. The given reaction will follow Markovnikov’s rule to form the desired product as shown below.
Figure 3
The product formed by the given reaction is shown in Figure 3.
Want to see more full solutions like this?
Chapter 5 Solutions
Organic Chemistry, Ebook And Single-course Homework Access
- Draw the monomers required to synthesize this condensation polymer.arrow_forward8:44 PM Sun Apr 13 Earn Freecash.com O Measurement and Matter =1 Setting up a unit conversion 110 Eddie says... ✰ www-awu.aleks.com A student sets up the following equation to convert a measurement. (The ? stands for a number the student is going to calculate.) Fill in the missing part of this equation. Note: your answer should be in the form of one or more fractions multiplied together. (- 4 J kJ -7.0 × 10 ☐ = ? mmol.°C mol °C x10 μ Explanation Check □·□ torox.io Grey Hill LLC. All Rightsarrow_forwardPolymers may be composed of thousands of monomers. Draw three repeat units (trimer) of the polymer formed in this reaction. Assume there are hydrogen atoms there are hydrogen atoms on the two ends of the trimer. Ignore inorganic byproducts please.arrow_forward
- i need help on how to complete the followingarrow_forwardno AI walkthrough current image is wrong answerarrow_forwarda. Determine whether each of the Followery Molecules is in the R- On the y- Configuration 1-01"/ 1-6-4 Br 4 I el Br b. Draw The Fisher projection For all the Meso compounds that can exist FOR The Following molenlearrow_forward
- 1- Refer to the monosaccharides below to answer each of the following question(s): CH₂OH CHO CH₂OH CH₂OH 0 H- OH 0 0 HO- H H- -OH HO H HO H H OH HO- H CH₂OH H. OH HO H HO- H CH₂OH CH₂OH CH3 a. Sorbose b. Rhamnose c. Erythrulose d. Xylulose Classify each sugar by type; for example, glucose is an aldohexose. a. Xylulose is .. b. Erythrulose is . c. Sorbose is .. d. Rhamnose is .. 2- Consider the reaction below to answer the following question(s). CHO H OH CH₂OH CH₂OH HO- H HO HO + H. -OH HO OH HO. H OH OH H -OH H OH CH₂OH Q Z a. Refer to Exhibit 25-11. Place a triangle around the anomeric carbon in compound Q. Compound Z is: b. 1. the D-anomer. 2. the a-anomer. 3. the ẞ-anomer. 4. the L-anomer. c. Which anomer is the LEAST stable? d. Q and Z are cyclic examples of: a. acetals b. hemiacetals c. alditols d. hemialditolsarrow_forwardi need help identifying the four carbon oxygen bonds in the following:arrow_forwardImagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule HO H3N + The solution is... X O acidic OH O basic H3N-CH-C-O O neutral ○ (unknown) O acidic ○ basic CH2 CH 3-S-CH2 O neutral ○ (unknown) H3N O OH O acidic O basic Oneutral O (unknown) 0 H3N-CH-C-O CH3 CH CH3 O acidic O basic O neutral ○ (unknown) ? olo Ar BHarrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
