Chapter 5, Problem 5.26P

Interpretation Introduction

Interpretation:

The final temperature needed to reduce the volume of a sample of sulfur hexafluoride at constant pressure to $\text{2}\text{.50}\text{L}$ is to be calculated.

Concept introduction:

Charle’s law states that at constant pressure $\left(P\right)$ and when the amount of gas $\left(n\right)$ is fixed, the volume of gas is directly proportional to the absolute temperature $\left(T\right)$.

$V\propto T$ (1)

For two different values of volume and temperature equation (1) can be modified as follows:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (2)

Here,

$V_1$ is initial volume occupied by the gas molecules.

$V_2$ is the final volume occupied by the gas molecules.

$T_1$ is the initial temperature.

$T_2$ is the final temperature.

The conversion factor to convert $°\text{C}$ to Kelvin is as follows:

$T\left(\text{K}\right)=T\left(°\text{C}\right)+273.15$ (3)

The conversion factor to convert Kelvin to $°\text{C}$ is as follows:

$T\left(°\text{C}\right)=T\left(\text{K}\right)-273.15$ (4)