Explanation Given: The diameter of the pipe ( d ) is 6 in . Pressure at A ( p A ) is 10 psi . Velocity at point A ( V A ) is 6 ft/s . The diameter of the water stream is 0.5 in. Calculation: The following assumptions are made in the problem: Point B and D are open to atmosphere. so the pressure at point B and D are zero. p B = p D = 0 . The water column reaches the ultimate height, its loss his kinetic energy so the velocity at D is zero ( V D = 0 ) . The datum line pass through the point A and C , so z A & z C = 0 , z B = 3 in . , and z D = ( h + 3 ) in . Apply Bernoulli equation between A and D . p A ρ + V A 2 2 + g z A = p D ρ + V D 2 2 + g z D 10 lb / in . 2 × ( 12 in . 1 ft ) 2 ( 62.4 lb / ft 3 32.2 ft/s 2 ) + ( 6 ft/s ) 2 2 + 0 = 0 + 0 + 32.2 ft/s 2 × [ h + ( 3 in . × 1 ft 12 in . ) ] 761.076 = 32.2 h + 8.05 32.2 h = 753.026 h = 23.4 ft Thus, the height of the water column is 23.4 ft _ . Apply Bernoulli equation between A and B , to obtain the velocity at B ( V B ) . p A ρ + V A 2 2 + g z A = p B ρ + V B 2 2 + g z B 10 lb / in . 2 × ( 12 in . 1 ft ) 2 ( 62.4 lb / ft 3 32.2 ft/s 2 ) + 6 2 2 + 0 = 0 + V B 2 2 + 32

2nd Edition

ISBN: 9780134649290

Author: Russell C. Hibbeler

Publisher: PEARSON

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Applied Fluid Mechanics

A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

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Chapter 5, Problem 51P

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The height h of the water column and the average velocity at C(VC).

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The height h of the water column and the average velocity at C ( V C ) .

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The height h of the water column and the average velocity at C(VC).

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