To determine The power output of the engine. Explanation Given: The enthalpy of fuel ( h A ) at inlet is 600 kJ / kg . The rate of heat loss ( Q i n ) as 1.5 kJ / s . The velocity at point A ( V A ) is 12 m/s. The enthalpy of fuel ( h B ) at outlet is 450 kJ / kg . The velocity at point A ( V B ) is 48 m/s. The mass flow rate ( m ˙ ) is 2 kg/s . Calculation: Since the engine is placed as horizontal position, Datum line at A and B is in same horizontal line. z A = z B Write the energy balance equation for the given system. Q i n − W o u t = { ( h B + V B 2 2 + g z B ) − ( h A + V A 2 2 + g z A ) } × m ˙ − ( 1

2nd Edition

ISBN: 9780134649290

Author: Russell C. Hibbeler

Publisher: PEARSON

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Chapter 5, Problem 12FP

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