(i) The root-mean-square speeds and average kinetic energies of the Helium both compared. (ii) The frequency and force has to be compared. Concept Introduction: Root mean-square speed is the parameter to measure the speed of particles in a gas. M is the molecular mass of the molecule at temperature T, root mean-square speed ( u rms ) has to be calculate using the formula u rms = 3RT M
(i) The root-mean-square speeds and average kinetic energies of the Helium both compared. (ii) The frequency and force has to be compared. Concept Introduction: Root mean-square speed is the parameter to measure the speed of particles in a gas. M is the molecular mass of the molecule at temperature T, root mean-square speed ( u rms ) has to be calculate using the formula u rms = 3RT M
Solution Summary: The author explains that the root-mean-square speed and average kinetic energies of the Helium are compared. The frequency and force of collisions are measured.
(i) The root-mean-square speeds and average kinetic energies of the Helium both compared.
(ii) The frequency and force has to be compared.
Concept Introduction:
Root mean-square speed is the parameter to measure the speed of particles in a gas. M is the molecular mass of the molecule at temperature T, root mean-square speed (urms) has to be calculate using the formula
urms=3RTM
(b)
Interpretation Introduction
Interpretation:
(i) The frequency and force of helium has to be compared.
(ii) The frequency and force has to be compared.
(c) The given statement valid
Concept Introduction:
The main useful of the idea is in the study of the standard impact force during collisions. Used for collisions, the mass and change in velocity are often willingly measured, other than the force during the collision is not.
(c)
Interpretation Introduction
Interpretation:
The given statement has to be valid.
Concept Introduction:
Root mean-square speed is the parameter to measure the speed of particles in a gas. M is the molecular mass of the molecule at temperature T, root mean-square speed (urms) has to be calculate using the formula
Part I.
a) Elucidate
the structure of compound A using the following information.
• mass spectrum: m+ = 102, m/2=57
312=29
• IR spectrum:
1002.5
% TRANSMITTANCE
Ngg
50
40
30
20
90
80
70
60
MICRONS
5
8
9 10
12
13
14 15 16
19
1740 cm
M
10
0
4000
3600
3200
2800
2400
2000
1800
1600
13
• CNMR
'H
-NMR
Peak
8
ppm (H)
Integration
multiplicity
a
1.5 (3H)
triplet
b
1.3
1.5 (3H)
triplet
C
2.3
1 (2H)
quartet
d
4.1
1 (2H)
quartet
& ppm (c)
10
15
28
60
177 (C=0)
b) Elucidate the structure of compound B using the following information
13C/DEPT NMR 150.9 MHz
IIL
1400
WAVENUMBERS (CM-1)
DEPT-90
DEPT-135
85 80 75
70
65
60
55
50
45 40
35
30 25 20
ppm
1200
1000
800
600
400
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Could you redraw these and also explain how to solve them for me pleas
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