WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119490579
Author: Mays
Publisher: WILEY
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Chapter 5, Problem 5.1.3P
To determine
The uniform flow depth in the rectangular channel.
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(b) Sketch the water surface profile with all necessary information and labels shown
A 8-meter-wide concrete rectangular channel with bed slope of 0.0008 mm/mm has a steady discharge of 8 m³/s. The manning's roughness constant (n) is 0.012.
a. Determine the normal depth of flow using Newton-Raphson Method. Use initial trial depth as 1.1 m. (Only two iterations are required)
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Chapter 5 Solutions
WATER RESOURCES ENGINEERING
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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- Uniform flows occur in a 10 meter wide rectangle channel. The flow in the channel is 18.4 m³/s and the depth of flow is 1.2 m. Roughness coefficient n = 0.012. Calculate the slope of the channel.arrow_forward5.1.3 Determine the uniform flow depth in a rectangular channel 2.5 ;m wide with a discharge of 3 m³/s. The slope is 0.004 and Manning's roughness factor is 0.015.arrow_forward2.1. A trapezoidal channel conveys 15 m³/s of water on a bed slope of 1 in 300. The base width of the channel is 5 m and the side slope is 2 m. Assume a Manning's roughness coefficient (n) of 0.018. Calculate: (a) Calculate the normal flow depth and discharge. (b) Calculate Reynold's and Froude Numbers. (c) Comment on the applicability of Manning's Equation.arrow_forward
- 2) For a rectangular open channel the following information is given: Discharge, Q=125 m³/s, cross-section width, b = 10 m, Manning roughness coefficient n = 0.025, channel bottom slope So = 0.00015. Determine: a) Uniform flow depth, yn. (For the first iteration assume yn = 10 m) b) State of the flow. c) Resistance to the flow, t. 个 yn ↓ IK 3-91arrow_forwardThe base of the artificial channel has a bottom width of 3m and sides with a slope of 1 vertical to 2 horizontal. The depth of water being predicted/estimated is 1.2m when the discharge is 3.51m3/s. Using Manning's equation with n = 0.022 a. Calculate the slope of the channel bed.b. Calculate the discharge in m3/s when the depth of flow is 1.3m.arrow_forwardA trapezoidal is shown below. The particulars of the channel are as such: • Side slopes are 1 in 0.5 m. Manning's n = 0.015 • Slope of channel is 1 m in 1 km 0.5 b a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determin the following: i. ii. iii. Discharge Mean Velocity Reynolds No. b. If the discharge were 35 m³/s and bottom width was 5m, what would the normal depth of flow be? All other conditions remain the same.arrow_forward
- The discharge in a channel with bottom width 3 m is 12 m³ s¹. If Manning's n is 0.013 m-1/3 s and the streamwise slope is 1 in 200, find the normal depth if: (a) the channel has vertical sides (i.e. rectangular channel); (b) the channel is trapezoidal with side slopes 2H:1V.arrow_forwardthe incoming flow rate is 100m3/s on a rectangular channel with: depth = 3m width = 4 meters Then, a hydraulic jump occurred along the way. Determine the depth at the hydraulic jump section.arrow_forwardA rectangular flume 2 m wide carries discharge at the rate of 2 m³/s. The bed slope of the flume is 0.0004. At a certain section the depth of flow is 1 m. Calculate the distance of the section downstream where the depth of flow is 0.9 m. Solve by single step method. Assume rugosity coefficient as 0.014. Is the slope of the channel mild or steep? How is this type of surface profile Classified ?arrow_forward
- A trapezoidal channel having a bottom slope of 0.001 is carrying a flow of 30 m³/s. The bottom width is 10.0 m and the side slopes are 2H to 1V. A control structure is built at the downstream end which raises the water depth at the downstream end to 5.0 m. Compute the water surface profile till 1.20 m. Manning n is 0.013 and a = 1. Select an appropriate Ay for your calculations.arrow_forwardx=30arrow_forwardQ. No 1). Determine the discharge through a trapezoidal channel having X m base width, Side slope is 2:1 (Vertical to Horizontal). If the height of free surface of the water above the bed is 4 m. The bed slope is 1 in 1500, take n= 0.012. Width X=85arrow_forward
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