Engineering Electromagnetics
Engineering Electromagnetics
9th Edition
ISBN: 9780078028151
Author: Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher: Mcgraw-hill Education,
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Chapter 5, Problem 5.10P

A large brass washer has a 2-cm inside diameter, a 5-cm outside diameter, and is 0.5 cm thick. Its conductivity is σ= 1.5 Ă— 107 S/m. The washer is cut m half along a diameter, and a voltage is applied between the two rectangular faces of one part. The resultant electric field in the interior of the half-washer is E = (0.5/p) a0 V/n in cylindrical coordinates, where the z axis is the axis of the washer, (a) What potential difference exists between the two rectangular faces? (b) What total current is flowing? (c) What is the resistance between the two faces?

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"Can you explain the integration method to show the result?" The radiation intensity of an aperture antenna, mounted on an infinite ground plane with perpendicular to the aperture, is rotationally symmetric (not a function of 4), and it is given by U = π sin Find the approximate directivity (dimensionless and in dB) using (a) numerical integration. Use the DIRECTIVITY computer program at the end of this chapter. U sin ( sin ) sin (a) Directly Do = 14.0707 = 10log (14.0707) = 11.48 dB
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complete the table in the attached photos. instructions are below the table

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