By analyzing given chemical equation the final volume of gas should be determined. Concept introduction: In 1811 the Italian chemist Avogadro introduced a gaseous law with interpreting the relationship between the number of moles and the volume of a gas at constant temperature and pressure. That is the volume of gas towards the amount of substance present. This law is known as Avogadro’s law . Avogadro’s law can be defined as, A gas kept in the particular container at constant pressure and temperature. If the amount (number of moles) of gas in the container is increased, the number of moles in the unit area of container is increased and the volume of container is increased. That is the volume of container is directly proportional to the number of moles of gas. As increasing the amount of substance of gas or the number of moles of gas, the volume of gas will expand. This direct relationship between the number of moles of gas and volume of gas is termed as Avogadro’s law . Mathematically this law can be written as, V ∝ n V = a n By rearranging, V n =a Where n is the number of moles of gas and a is proportionality constant. By comparing two systems at different conditions, V 1 n 1 = V 2 n 2
By analyzing given chemical equation the final volume of gas should be determined. Concept introduction: In 1811 the Italian chemist Avogadro introduced a gaseous law with interpreting the relationship between the number of moles and the volume of a gas at constant temperature and pressure. That is the volume of gas towards the amount of substance present. This law is known as Avogadro’s law . Avogadro’s law can be defined as, A gas kept in the particular container at constant pressure and temperature. If the amount (number of moles) of gas in the container is increased, the number of moles in the unit area of container is increased and the volume of container is increased. That is the volume of container is directly proportional to the number of moles of gas. As increasing the amount of substance of gas or the number of moles of gas, the volume of gas will expand. This direct relationship between the number of moles of gas and volume of gas is termed as Avogadro’s law . Mathematically this law can be written as, V ∝ n V = a n By rearranging, V n =a Where n is the number of moles of gas and a is proportionality constant. By comparing two systems at different conditions, V 1 n 1 = V 2 n 2
Solution Summary: The author explains Avogadro's gaseous law, which is based on the relationship between the number of moles and the volume of a gas at constant temperature and pressure.
Definition Definition Number of atoms/molecules present in one mole of any substance. Avogadro's number is a constant. Its value is 6.02214076 × 10 23 per mole.
Chapter 5, Problem 50E
Interpretation Introduction
Interpretation: By analyzing given chemical equation the final volume of gas should be determined.
Concept introduction:
In 1811 the Italian chemist Avogadro introduced a gaseous law with interpreting the relationship between the number of moles and the volume of a gas at constant temperature and pressure. That is the volume of gas towards the amount of substance present. This law is known as Avogadro’s law.
Avogadro’s law can be defined as,
A gas kept in the particular container at constant pressure and temperature. If the amount (number of moles) of gas in the container is increased, the number of moles in the unit area of container is increased and the volume of container is increased. That is the volume of container is directly proportional to the number of moles of gas. As increasing the amount of substance of gas or the number of moles of gas, the volume of gas will expand. This direct relationship between the number of moles of gas and volume of gas is termed as Avogadro’s law.
Mathematically this law can be written as,
V∝n
V=an
By rearranging,
Vn=a
Where n is the number of moles of gas and a is proportionality constant.
Relative Intensity
Part VI. consider the multi-step reaction below for compounds
A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
100
HS-NJ-0547
80
60
31
20
S1
84
M+
absent
10
30
40
50
60
70
80
90
100
100-
MS2016-05353CM
80-
60
40
20
135 137
S2
164 166
0-m
25
50
75
100
125
150
m/z
60
100
MS-NJ-09-43
40
20
20
80
45
S3
25
50
75
100
125
150
175
m/z
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
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